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Sever21 [200]
3 years ago
9

A body covers a semicircle of radius 7cm in 5s .find its linear speed

Physics
1 answer:
choli [55]3 years ago
8 0

Ok so we are given the radius of 7cm and time of 5 seconds.

From the data we got we can calculate speed, frequency, perimeter and area of the semicircle.

Let's start with perimeter.

We know that perimeter of circle is 2\pi r so the perimeter of semicircle is \dfrac{2\pi r}{2} or simply \pi r

So the perimeter is equal to:

\pi r=\pi\cdot7\approx\boxed{22cm}

So this is the length of a curve or let's say the distance.

Now let's look at the linear speed s=\dfrac{d}{t} where d is distance and t time.

We know the distance and we know the time.

So let's calculate it.

s=\dfrac{d}{t}=\dfrac{22}{5}=\boxed{4.4\dfrac{cm}{s}}

Hope this helps.

r3t40

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3 years ago
6. Decelerating a plane at a uniform rate of -8 m/s2, a pilot stops the plane in 484 m. How
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Answer: 88 m/s

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If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

V_{o} Is the initial velocity of the plane

a=-8m/s^{2} is the constant acceleration of the plane

d=484m is the distance at which the plane stops

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