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victus00 [196]
3 years ago
11

Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?

Physics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

the image can be rather real or virtual

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Select all that apply. Which of the following would increase the conductivity of a connecting wire?
lord [1]
What are your choices 

4 0
3 years ago
Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equ
lesantik [10]

Answer:

The magnitude of the force on positive charges will be \bf{227.06~N} and the magnitude of the force on the negative charge is \bf{302.7~N}.

Explanation:

Given:

The value of the charges, q = 3.5~\mu C.

The length of each side of the triangle, l = 2.9~cm.

Consider a equilateral triangle \bigtriangleup ABC, as shown in the figure. Let two point charges of magnitude q are situated at points A and B and another point charge -q is situated at point C.

The value of the force on the charge at point A due to charge at point C is given by

F_{CA} = \dfrac{kq^{2}}{l^{2}},~~along~CA

The value of the force on the charge at point A due to charge at point B is given by

F_{BA} = \dfrac{kq^{2}}{l^{2}},~~along~BA

The net resultant force on the charge at point A is given by

~~~~F_{A} = \sqrt{F_{BA}^{2} + F_{CA}^{2} + 2F_{BA}F_{CA}\cos 60^{0}}\\~~~~~= \dfrac{kq^{2}}{l^{2}}\sqrt{2(1 + \cos 60^{0})}\\or, F_{A}= \dfrac{\sqrt{3}kq^{2}}{l^{2}}~~~~~~~~~~~~~~~~~~~~(1)

The value of the force on the charge at point B due to charge at point C is given by

F_{CB} = \dfrac{kq^{2}}{l^{2}},~~along~CB

The value of the force on the charge at point B due to charge at point A is given by

F_{AB} = \dfrac{kq^{2}}{l^{2}},~~along~AB

The net resultant force on the charge at point B is given by

~~~~F_{B} = \sqrt{F_{AB}^{2} + F_{CB}^{2} + 2F_{AB}F_{CB}\cos 60^{0}}\\~~~~~= \dfrac{kq^{2}}{l^{2}}\sqrt{2(1 + \cos 60^{0})}\\or, F_{B}= \dfrac{\sqrt{3}kq^{2}}{l^{2}}~~~~~~~~~~~~~~~~~~~~(2)

The value of the force on the charge at point C due to charge at point A is given by

F_{AC} = \dfrac{kq^{2}}{l^{2}},~~along~AC

The value of the force on the charge at point C due to charge at point B is given by

F_{BC} = \dfrac{kq^{2}}{l^{2}},~~along~BC

The net resultant force on the charge at point C is given by

F_{C} = 2F_{BC} \sin 60^{0}~~along~the~line~perpendicular~to~AB\\~~~~~= \dfrac{2kq^{2}}{l^{2}}\sin 60^{0}~~~~~~~~~~~~~~~~~~~~(3)

Substitute 3.5~\mu C for  q , 0.029~m for  l  and 9 \times 10^{9}~Nm^{2}C^{-2} for k in equation (1), we have

F_{A} = \dfrac{\sqrt{3}(9 \times 10^{9}~Nm^{2}C^{-2})(3.5 \times 10^{-6}~C)^{2}}{(0.029~m)^{2}}\\~~~~~= 227.06~N

Substitute 3.5~\mu C for  q , 0.029~m for  l  and 9 \times 10^{9}~Nm^{2}C^{-2} for k in equation (2), we have

F_{B} = \dfrac{\sqrt{3}(9 \times 10^{9}~Nm^{2}C^{-2})(3.5 \times 10^{-6}~C)^{2}}{(0.029~m)^{2}}\\~~~~~= 227.06~N

Substitute 3.5~\mu C for  q , 0.029~m for  l  and 9 \times 10^{9}~Nm^{2}C^{-2} for k in equation (3), we have

F_{C} = \dfrac{2(9 \times 10^{9}~Nm^{2}C^{-2})(3.5 \times 10^{-6}~C)^{2}}{(0.029~m)^{2}} \sin 60^{0}\\~~~~~= 302.7~N

8 0
3 years ago
Why are mercury and the earths moon so cratered?
Ksenya-84 [330]
They are cratered because of meteoroids, neither of them have an atmosphere to disintegrate the meteors, and neither of them have water to erode the craters.
8 0
3 years ago
First, find the magnitude of v⃗ , that is, the speed v of the two-car unit after the collision.
Rufina [12.5K]

The magnitude of v⃗ is {sqrt(m1v1)2+(m2v2)2/ m1+m2}, that is, the speed v of the two-car unit after the collision.

<h3>What is collision?</h3>
  • In physics, collisions occur when particles, aggregates of particles, or solids come close to each other, interact and affect each other.
  • Collisions are of three types Fully elastic collision, inelastic collision and Perfectly inelastic collision.
  • Multiply the mass of the second object by its velocity.
  • For example, if the weight is 1,000 and the speed is -30 meters per second, then its momentum is 30,000 kg meters per second.
  • Add the two velocities together to determine  the direction the object will move after a collision.
  • So the formula for determining the size of a vector (in 2D space) is v = (x, y).|v| = √(x2 + y2).
  • This formula is derived from the Pythagorean theorem.
  • The formula  V = (x, y, z) that determines the size of a vector (in 3-dimensional space) is:|V| = √(x2 + y2 + z2)

To learn more about collision from the given link :

brainly.com/question/13138178

#SPJ4

3 0
1 year ago
Which one is series and which one is parallel ( i give 20 points who answer )
slega [8]

Answer:

figure (a) L1 is series and L2 is parallel to L3

figure (b) L2 and L3 are parallel to L1

4 0
2 years ago
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