They will be forming a right triangle.
long leg is the height of Lyra. 22 meters high from the entrance.
short leg is the distance of Donna. 50 meters from the entrance.
We need to solve for the hypotenuse or the range of communication.
a² + b² = c²
22² + 50² = c²
484 + 2500 = c²
2,984 = c²
√2,984 = √c²
54.63 = c
The range of communication for the two radios is 55 meters.
Answer:
Tom = 5
Susan = 3
Step-by-step explanation:
FROM THE BOXPLOT :
Tom's IQR :
IQR = Q3 - Q1
Q3 = third quartile (value at the endpoint of the box)
Q1 = 1st quartile (value at the beginning of the box)
IQR = 9 - 4
IQR = 5
SUSAN :
IQR = Q3 - Q1
Q3 = third quartile (value at the endpoint of the box)
Q1 = 1st quartile (value at the beginning of the box)
IQR = 8 - 5
IQR = 3
Answer:
t=-9
Step-by-step explanation:
2(2t-3)=6(t+2)
4t-6=6t+12
4t-6t=12+6
-2t=18
t=-9
<h2>
Answer:</h2>
a. <-13/2,-13/2>
<h2>
Step-by-step explanation:</h2>
The projection of a vector u onto another vector v is given by;
=
----------------(i)
Where;
u.v is the dot product of vectors u and v
|v| is the magnitude of vector v
Given:
u = <-6, -7>
v = <1, 1>
These can be re-written in unit vector notation as;
u = -6i -7j
v = i + j
<em>Now;</em>
<em>Let's find the following</em>
(i) u . v
u . v = (-6i - 7j) . (i + j)
u . v = (-6i) (1i) + (-7j)(1j) [Remember that, i.i = j.j = 1]
u . v = -6 -7 = -13
(ii) |v|
|v| = ![\sqrt{(1)^2 + (1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%281%29%5E2%20%2B%20%281%29%5E2%7D)
|v| = ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
<em>Substitute these values into equation (i) as follows;</em>
= ![[\frac{-13}{(\sqrt{2}) ^2}][i + j]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B-13%7D%7B%28%5Csqrt%7B2%7D%29%20%5E2%7D%5D%5Bi%20%2B%20j%5D)
= ![\frac{-13}{2} [i + j]](https://tex.z-dn.net/?f=%5Cfrac%7B-13%7D%7B2%7D%20%5Bi%20%2B%20j%5D)
This can be re-written as;
= ![\frac{-13}{2}i + \frac{-13}{2}j](https://tex.z-dn.net/?f=%5Cfrac%7B-13%7D%7B2%7Di%20%2B%20%5Cfrac%7B-13%7D%7B2%7Dj)
= ![](https://tex.z-dn.net/?f=%3C%5Cfrac%7B-13%7D%7B2%7D%2C%20%5Cfrac%7B-13%7D%7B2%7D%3E)