2 years ago

Why are images “flipped upside down” with a lens and how do you “flip them back over”?

1 answer:

Crank2 years ago

3 0

You go to the image, click edit, then you click this square with arrows around it, then you look up at the left corner of your screen and you click the square with the arrow and adjust the image to your liking.

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A water wave has a speed of 23.0 meters/second. If the wave’s frequency is 0.0680 hertz, what is the wavelength?

tankabanditka [31]

Using the Fundamental Equation of Wave, we have:

$v=\lambda f \\ \lambda= \frac{23}{0.068} \\ \boxed {\lambda \approx 338m}$

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Where is the value of kinetic energy equal to zero

bearhunter [10]

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if the object is not in motion

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The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.

Natali [406]

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2 years ago

What are the foci of the ellipse given by the equation 100x^2 + 64y^2 = 6 400?

NikAS [45]

The equation of our ellipse is:

$100 x^2 + 64 y^2 = 6400$ (1)

First, let's reduce the equation of the ellipse to the standard form:

$\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1$

To do that, we should divide both terms of equation (1) by 6400, and we get:

$\frac{x^2}{64}+ \frac{y^2}{100}=1$

This is a vertical ellipse (because $b^2 \ \textgreater \ a^2$ ) centered in the origin, and so the distance of its foci from the origin (on the y axis) is given by

$c= \sqrt{b^2-a^2}= \sqrt{(100)-(64)}=6$

Therefore, the position of the two foci is (0,6) and (0,-6)

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