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3 years ago

8.71 x 10^7 in standard form! Please hurry.

Mathematics

1 answer:

olchik [2.2K]3 years ago

8 0

Answer:

87, 100,000

Step-by-step explanation:

Brainliest please! Visit my church's website at fbcinterlaken.org to learn more about God! It would mean a lot! Thank you and have a nice day! :)

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How is 2-2×6+3=-7?<br>The answer to this question

alekssr [168]

Answer:

PEMDAS

Step-by-step explanation:

Using PEMDAS or the order of operations, you first multiply 2 by 6

2-2×6+3

2-12+3

Then you can go in any order since addition and subtraction take the same precedence.

-10+3=-7

5 0

4 years ago

From 175 yards away, a marksman hit 14/50 of the targets last year.

Maurinko [17]

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2 years ago

I need help please and thank you

taurus [48]

Answer:

are you on edge

Step-by-step explanation:

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3 years ago

Solve the equation for the indicated variable S=2πrh+2πr²<br> Solve for h

valina [46]

Answer:

Good luck :)

Step-by-step explanation:

S=2πrh+2πr ²

subtract 2πr ² from each side

S -2πr ² = 2πrh

divide by 2πr from each side

(S -2πr ² )/ 2πr = h

4 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago