C. Model. It's a graphical model that displays one or more weather elements.
To move around more. bounce off walls ect. they are more energised
Answer:
V₂ = 50.93 L
Explanation:
Initial volume, ![V_1=43.1\ L](https://tex.z-dn.net/?f=V_1%3D43.1%5C%20L)
Initial temperature, ![T_1=24^{\circ} C=24+273=297\ K](https://tex.z-dn.net/?f=T_1%3D24%5E%7B%5Ccirc%7D%20C%3D24%2B273%3D297%5C%20K)
Final temperature, ![T_2=78^{\circ} C=78+273=351\ K](https://tex.z-dn.net/?f=T_2%3D78%5E%7B%5Ccirc%7D%20C%3D78%2B273%3D351%5C%20K)
We need to find the final volume of the gas. The relation between the volume and the temperature is given by :
![\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L](https://tex.z-dn.net/?f=%5Cdfrac%7BV_1%7D%7BT_1%7D%3D%5Cdfrac%7BV_2%7D%7BT_2%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7BV_1T_2%7D%7BT_1%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7B43.1%5Ctimes%20351%7D%7B297%7D%5C%5C%5C%5CV_2%3D50.93%5C%20L)
So, the final volume of the gas is 50.93 L.
2H2O --> 2H2 + O2
The mole H2O:mole O2 ratio is 2:1
Now determine how many moles of O2 are in 50g: 50g × 1mol/32g = 1.56 moles O2
Since 1 mole of O2 was produced for every 2 moles of H2O, we need 2×O2moles = H2O moles
2×1.56 = 3.13 moles H2O
Finally, convert moles to grams for H2O:
3.13moles × 18g/mol = 56.28 g H2O
D) 56.28
Could I hear the options..