The question is: To neutralize 20ml of 0.1M HCl solution, 10ml of NaOH solution of concentration x mol/l is required. What is the value of x?
Answer: The value of x is 0.2 M.
Explanation:
Given: 
= 20 mL, 
= 0.1 M
= 10 mL, 
= x
Formula used is as follows.
Thus, we can conclude that the value of x is 0.2 M.
The vapor of acetic acid will go to the floor of the room.
This is because the density of acetic acid vapor is equal to 2.07 is higher (almost twice) than the density of air which is equal to only 1
D. Not all mixtures are heterogeneous
Answer:
0.501 L
Explanation:
To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".
V∝ 1/P
V= K/P
VP=K
Here the K is proportionality constant.
so,
P1V1 = P2V2
P= pressure
V= volume
Given data:
P1= 1 atm
V1= 461 mL
P2= 0.92 atm
V2= ? (L)
To solve this problem we have to convert the mL into L first.
1 L = 1000 mL
461/1000= 0.461 L
Now we will put the values in the equation,
P1V1 = P2V2
V2= P1V1/ P2
V2= 1 atm × 0.461 L / 0.92 atm
V2= 0.501 L
