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sammy [17]
3 years ago
7

Joebert had a rectangular cup and filled it with water. He measured the water's mass and volume. Then he got a density of 1.25g/

ml. If the accepted density of water is 1 g/ml, what was the percent error of his measurement?
someone can help me please?
Chemistry
1 answer:
ANTONII [103]3 years ago
5 0

Answer:

Percent error = 25%

Explanation:

Given data:

Measured density of water = 1.25 g/mL

Accepted density value of water = 1 g/mL

Percent error = ?

Solution:

Formula:

Percent error = (measured value - accepted value / accepted value) × 100

Now we will put the values in formula:

Percent error = (1.25 g/mL - 1 g/mL /1 g/mL )× 100

Percent error = (0.25 g/mL /1 g/mL )× 100

Percent error = 0.25 × 100

Percent error = 25%

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Katyanochek1 [597]

Answer:

The answer to your question is     V2 = 4.97 l

Explanation:

Data

Volume 1 = V1 = 4.40 L                    Volume 2 =

Temperature 1 = T1 = 19°C               Temperature 2 = T2 = 37°C

Pressure 1 = P1 = 783 mmHg           Pressure 2 = 735 mmHg

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = 37 + 273 = 310°K

2.- Use the combined gas law to solve this problem

                  P1V1/T1  = P2V2/T2

-Solve for V2

                  V2 = P1V1T2 / T1P2

-Substitution

                  V2 = (783 x 4.40 x 310) / (292 x 735)

-Simplification

                 V2 = 1068012 / 214620

-Result

                 V2 = 4.97 l

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What inorganic molecule is carbon normally found in?
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It’s CO2

Carbon dioxide

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<img src="https://tex.z-dn.net/?f=%5Chuge%7B%5Cboxed%7B%5Cmathfrak%7BQuestion%3A%7D%7D%7D%5C%20%20%5Ctextless%20%5C%20br%20%2F%5
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Explanation:

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Read 2 more answers
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