Answer:
Partial pressure Ne = 340 Torr
Option B
Explanation:
Gases contained in the vessel:
N₂, Ar, He, Ne
One of Dalton's law for gases determine this:
In a mixture of gases contained in a vessel, total pressure of the system must be the sum of partial pressure of each gas.
Total pressure = 1100 Torr
Let's replace:
Partial pressure N₂ + Partial pressure Ar + Partial pressure He + Partial pressure Ne = 1100 Torr
Partial pressure Ne = 1100 Torr - Partial pressure N₂ - Partial pressure Ar -Partial pressure He
Partial pressure Ne = 1100 Torr - 110 Torr - 250 Torr - 400 Torr
Partial pressure Ne = 340 Torr
Digestion would be correct. Hope this helps
Answer:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Explanation:
From the question given above,
Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
Thus, we can balance the above equation as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu
There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Thus, the equation is balanced.
V=650 ml = 0.65 l
c=0.4 mol/l
n=vc
n=0.65 l * 0.4 mol/l = 0.26 mol
mass MgCl₂ = mol x MM MgCl₂ = 0.05 x 95.211 g/mol = 4.76 g
mass Cl in MgCl₂ :
= (2 x AM Cl)/MM MgCl₂ x mass MgCl₂
= (2 x 35.5 g/mol)/95.211 g/mol x 4.76
= 3.55 g
% mass Cl in the mixture :
= (mass Cl / mass mixture) x 100%
= 3.55 / 9.8 x 100%
= 36.22%
