Answer:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Explanation:
From the question given above,
Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
Thus, we can balance the above equation as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu
There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Thus, the equation is balanced.
