Answer:
Specific heat of calcium carbonate(C) = 0.82 (Approx)
Explanation:
Given:
Energy absorbs (q) = 85 J
Change in temperature (Δt) = 34.9 - 21 = 13.9°C
Mass of calcium carbonate = 7.47 g
Find:
Specific heat of calcium carbonate(C)
Computation:
Specific heat of calcium carbonate(C) = q / m(Δt)
Specific heat of calcium carbonate(C) = 85 / (7.47)(13.9)
Specific heat of calcium carbonate(C) = 85 / 103.833
Specific heat of calcium carbonate(C) = 0.8186
Specific heat of calcium carbonate(C) = 0.82 (Approx)
The chemical formula for table sugar is C12H22O11. From the formula, you can say that it is an organic molecule where in every molecule contains 12 atoms of carbon, 22 atoms of hydrogen and 11 atoms of oxygen. There are 45 atoms in total in one molecule of sugar.
0.24J/g*degC * 4.37g * 2.5degC = 2.622J
The 2.5 degC is the difference between 25 and 27.5 deg C.
Answer:
Explanation:
Hello,
In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:
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