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3 years ago

13

Just need to know net force, balanced or unbalanced and accelerated or not accelerated! look at picture :)

1 answer:

Gwar [14]3 years ago

8 0

Answer:

3. Net force 65 N right

Unbalanced

Accelerate

4. Net force 4 N downish lol

Unbalanced

Accelerate

5. Net force 21 N left

Unbalanced

Accelerate

6. Net force 8 N down

Unbalanced

Accelerate

7. Net force 0 N

Balanced

Not accelerate

8.

Net force 0 N

Balanced

Not accelerate

Explanation:

Hope this helps!

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How does free energy challenge the scientific definition of energy?

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I may not be completely sure but compare those 2 things together and you should find your answer.

7 0

3 years ago

From the edge of a cliff, a 0.46 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up

wel

Answer:

Explanation:

Given

mass of Projectile(m)=0.46 kg

Initial Kinetic Energy=1430 J

Maximum upward displacement from Launch point=150 m

$K.E.=\frac{mv^2}{2}$

$1430\times 2=0.46\times v^2$

v=78.85 m/s

and $H_{max}=\frac{v^2\sin ^2\theta }{2g}$

$150=\frac{(78.85)^2\sin ^2\theta }{2\times 9.8}$

$\sin \theta =0.687$

$\theta =43.39^{\circ}$

initial horizontal velocity $(v_x)=v\cos \theta$

$v_x=78.84\times \cos (43.39)=57.29 m/s$

Initial vertical velocity $(v_y)=v\sin \theta$

$v_y=78.85\times \sin (43.39)$

$v_y=54.16 m/s$

(c)vertical velocity at any instant=65 m/s

Since initial vertical velocity is 54.16 m/s

so 65 m/s will be acquired when projectile started falling below cliff

$v^2-u^2=2 a s$

$65^2-54.16^2=2\times 9.8\times s$

$s=65.90 m$

7 0

3 years ago

A motorcycle is travelling at a constant velocity of 90 km/h (no acceleration). How many

Mazyrski [523]

2km*1000=2000m
S=ut+1/2at^2
a=0,thus s=ut
2000=90t
t=2000/90
=22.22s(to 4 s.f)
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8 0

3 years ago

A wave has a wavelength of 11 mm and a frequency of 11 hertz. What is its speed?

eimsori [14]

Wave speed = frequency (in Hz) x wavelength (in m) so wave speed = 11 x 0.011 = 0.121 m/s

5 0

3 years ago

Read 2 more answers

A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg

slava [35]

Answer:

Explanation:

mass of first marble $m_1=m=0.015\ kg$

Initial velocity of the first marble $u_1=22.5\ m/s$

considering right side as positive

Mass of second marble

$m_2=m=0.015\ kg\\u_2=-18\ cm/s$

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. $v_1=-18\ cm/s$

considering $v_2$ be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

$e=\frac{v_2-v_1}{u_1-u_2}$

Putting values

$1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s$

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy = $0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J$

Final kinetic energy=

$0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J$

6 0

3 years ago