I would say that B is the correct answer which means that the melting point would be intensive or that no matter how large or small the sample of the sulphur is, it will have a consistent melting temperature or of 115.2 degrees C.
I think it is a radiation poisoning
Answer:
0.05257 L/s
Explanation:
Step 1: Given data
The school uses 1200 gallons/day
Step 2: Convert "gal/day" to "L/day"
We will use the conversion factor 1 gal = 3.785 L.
1200 gal/day × (3.785L/gal) = 4542 L/day
Step 3: Convert "L/day" to "L/s"
We will use the following conversion factors:
4542 L/day × (1 day/24 h) × (1 h/3600 s) = 0.05257 L/s
Answer:
The answer is: 0,13 moles of CO2
Explanation:
We use the formula PV=nRT. The conditions STP are 1 atm of pressure and 273K of temperature:
PV=nRT n=PV/RT
n=1 atm x 2,8 L/ 0,082 l atm/K mol x 273K
n= 0,125078173 mol
