Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
9.5000032 is one such number
Answer: 6
Step by step:
W is width, l is length, p is perimeter
The perimeter of a rectangle is 2w+2l.
l=3w+9
2l=6w+18
2l+2w=8w+18
P=8w+18
66=8w+18
48=8w
W=6
Hope this helps.
Answer:
1-8x
Step-by-step explanation:
not sure ...........
Answer:
x = 30
Step-by-step explanation:
The diagonals are bisected so DE =EB
67 = 2x+7
Subtract 7
67-7 = 2x+7-7
60 =2x
Divide by 2
60/2 =2x/2
30 = x
