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3 years ago

Will give brainliest no files will report.

Mathematics

2 answers:

sashaice [31]3 years ago

8 0

Answer:

I believe your answer is D.

Step-by-step explanation:

I'm not great with these types of problems so I'd like to warn you- I'm not 100% sure, but with that being said, D is what I'd choose.

Alexandra [31]3 years ago

5 0

Answer:

Step-by-step explanation:

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Before sending in your payment to the credit card company, you go to a bicycle store. Approximately, how much can you spend befo

melisa1 [442]

Answer:

$0, you are already over your credit limit

Step-by-step explanation:

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3 years ago

Read 2 more answers

A football team must move the ball forward at least 10 yards from its starting point to

Vitek1552 [10]

Answer:

The team will not make the first down.

Here are the integers that are represented by the scenario.

-2 + -2 + -2 = -6

-6 + 12 = 6 yard gain.

They are 4 yards short of the first down

Step-by-step explanation:

7 0

3 years ago

A recipe calls for 5/6 cup of flour Dixie wants to make 3/5 dixie currently has 3/4 cups of flour does she have enough to make t

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

5/6 - 3/4

20 - 12 = 8

_____ __

24 24

Cancelling out, we have

=>1/3

She does not have enough cup of flour. She needs 1/3 more to be able to make the recipe.

Hope it helps 

5 0

3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

I'm in school and i need help cause I really bad at this : P

Alinara [238K]

Answer:

same:P

Step-by-step explanation:

4 0

3 years ago