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sergiy2304 [10]
3 years ago
5

Helpp me...

lass="latex-formula">
ka = 1
Soo :
hk + ka = ? ​
Mathematics
2 answers:
vredina [299]3 years ago
6 0
<h2>>> Answer </h2>

________

\:

hk = 2, ka = 1

soo :

hk + ka = ?

= 2 + 1

= 3

Marina86 [1]3 years ago
3 0

Answer:

3

Step-by-step explanation:

  • hk = 2
  • ka = 1

So

  • hk + ka

= hk + ka

= 2 + 1

= 3

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Evaluate each expression.<br> 8/7 + 4/7
Galina-37 [17]

Answer:

<u>1 4/7</u>

Step-by-step explanation:

8/7 + 4/7 = 12/7. Simplified = <u>1 4/7</u>

5 0
2 years ago
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I'm only good at answering not solving:,)
Mazyrski [523]

Answer:

1/3 chance for even 1/3 chance for odd

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2 years ago
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Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

8 0
3 years ago
If the discount is 36% and the sale price is $32 what was the original price
jok3333 [9.3K]

Answer:

89

Step-by-step explanation:

100/36= 2.77777778

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89

8 0
3 years ago
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Can you solve 35÷5+56÷7
VLD [36.1K]
Order of operations

first divide, than add

35/5 = 7
56/7 = 8

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15 is your answer

hope this helps
8 0
3 years ago
Read 2 more answers
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