Question

Verify sin(360° - 0) = -sin0​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the Addition formula for sine

sin(x ± y) = sinxcosy ± cosxsiny

Consider the left side

sin(360 - Θ ), then

= sin360°cosΘ - cos360°sinΘ

= 0 × cosΘ - 1 × sinΘ

= 0 - sinΘ = - sinΘ → verified

Answer 2

Answer:  $sin(360\°-\theta)=-sin\theta$ is TRUE (See the explanation)

Step-by-step explanation:

To verify $sin(360\°-\theta)=-sin\theta$ you need to use the following identity:

$sin(x\±y)=sin(x)\ cos(y)\±cos(x)\ sin(y)$

It is important to know that:

$sin(360\°)=0\\\\cos(360\°)=1$

Then, knowing this, you get:

$sin(360\°-\theta)=sin(360\°)\ cos\theta-cos(360\°)\ sin\theta=0\ cos\theta-1\ sin\theta=-sin\theta$

Therefore $sin(360\°-\theta)=-sin\theta$ is TRUE.