All categories

2 years ago

A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.

Physics

2 answers:

Tomtit [17]2 years ago

7 0

Bipolar outflow is the blank

podryga [215]2 years ago

3 0

Answer:

Hi, There! my name is Jay And I'm here to help!

<h2>Question</h2>

A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.

<h2>Answer</h2>

bipolar outflow

Explanation:

A bipolar outflow is a stream of matter in two opposing directions from a object, Most likely a star.

-------------------------------------------------------------------------------------------------------------

Hope this Helps!

Take Care!

Have a great day!

$-Jay-$

You might be interested in

What best describes desert pavements

Gekata [30.6K]

Answer:

Explanation:

A common theory suggests that desert pavements are formed through gradual removal of sand and other fine particles by the wind and intermittent rains leaving behind the large fragments. The larger rock particles are shaken into place by actions of different agents such as rain, wind, gravity, and animals

3 0

3 years ago

Suppose you were bungee jumping from a bridge while blowing a hand-held air horn. How would someone remaining on the bridge hear

Genrish500 [490]

Answer:

The pitch will progressively lower

Explanation:

If i were bungee jumping from a bridge while blowing a hand-held air horn and someone who remains on the bridge will hear a decreased pitch or frequency as the source is moving away from the stationary listener as per the Dooplers effect. Hence, the pitch will progressively lower as the source is moving away from the observer.

4 0

3 years ago

Read 2 more answers

A 0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s.

Reptile [31]

<span>Mass of the ball is m = 0.10kg Initial speed of the Ball v = 15m/s a. When the ball is at maximum height the velocity is 0 Momentum of ball = mass x velocity Momentum = 0.10kg x 0 = 0 b. Getting the maximum height, Using the conservation of energy equation KEinitial = mgh 1/2mVin^2 = mgh => h = v^2/2g h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m Applying the conservation of energy equation at halfway V^2 = 2gh V = square root of (2x9.8x5.96) => V = square root of (116.816) So the velocity at the half way V = 10.81 m/s Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s</span>

6 0

3 years ago

An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu

ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, $qE \times S + mg \times S = 0.5 \times mv^{2}$

$1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}$

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight and the above equation will be as follows.

$(1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2
}$