Answer:
4.2 L
Explanation:
Use Boyle's Law and rearrange formula.
- Hope this helps! Please let me know if you need further explanation.
I searched it up on Google and I got 473.176 Hope this helps.
Answer:
Copper(II) sulphate – sodium hydroxide reaction
The reaction between copper(Il) sulphate and sodium hydroxide solutions is a good place to start. If you slowly add one to the other while stirring, you will get a precipitate of copper(II) hydroxide, Cu(OH)2.
Given concentration of NaCl=15%
Means ,
In every 100g of Solution 15g of NaCl is present .
Now
So ,



<u>37.5g of NaCl present in 250g of solution.</u>