Answer:
Explanation:
The average atomic mass is the sum of the product of the given masses and their abundances. We have to complete two steps for each isotope, then add all the products together.
<u>Fe-54</u>
Convert the percent abundance to a decimal by dividing by 100.
Multiply the abundance as a decimal by the mass number. This is the number after the element in the isotope symbol (54 amu).
<u>Fe-56</u>
Convert the percent to a decimal.
Multiply the decimal by the mass number (56 amu).
- 0.91754 * 56= 51.38224 amu
<u>Fe-58</u>
Convert the percent to a decimal.
Multiply by the mass number (58 amu).
- 0.02119 * 58 = 1.22902 amu
<u>Average Atomic Mass</u>
Add all the products together to find the average atomic mass.
- 3.1563 amu + 51.38224 amu + 1.22902 amu =55.76756 amu
The average atomic mass given the percent abundance is <u>55.7656 atomic mass units.</u>
It is practical research of Boyle’s law..
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Answer:
Thermal decomposition or cracking
Explanation:
Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.
Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.
When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.
Example is given below:
C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄
Answer:
In Charles law, temperature and volume of the gas are kept at constant pressure. Where as in Boyle's law, pressure and volume of the gas are kept at a constant temperature. In Boyle's law, pressure and volume vary inversely where as, in Charles law, pressure and volume vary directly.
Answer:
The answer is below
Explanation:
Newton's second law of motion states that the force applied to an object is directly proportional to the rate of change of momentum with respect to time, going in the same direction as the force.
Let F = force, m = mass of object, v = velocity of object, mv = momentum.
F = d/dt(mv) = m(dv / dt) = ma; a = acceleration.
Let us assume that the object starts from rest to 5 m/s within 1 seconds, hence:
F = m(dv / dt)
200 N = m[(5 m/s - 0 m/s) / (1 s)]
200 = 5m
m = 40 kg
