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steposvetlana [31]
3 years ago
11

Collision 2: Blue Cart Moving Slower than the Red Cart

Physics
1 answer:
pshichka [43]3 years ago
3 0

Answer:

this is what i always used

Explanation:

http://www.sjutsscience.com/uploads/3/7/4/5/37458459/phet_collision_lab_2020_key.pdf

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In a 50 km/h head-on crash test, the steering column of passenger car 1 moved 3 cm upward and 2 cm rearward. The steering column
Softa [21]

Answer:

Car 1

Explanation:

The steering column which moves the least is less likely to to the driver's chest ordinarily. Driver tends to remain in motion until restrained. Assuming a  seat belt not airbag

Generally one would compute a vector find direction and distance.  This is like solving for a hypotenuse  / in a right angled triangle problem. On face value the column moving the least is safer. The 6/24 would hit the upper chest, face, or possibly break the neck.

hence, car 1 moved 3 cm upward and 2 cm rearward is safer.

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igomit [66]
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Find the work performed when the given force f f is applied to an object, whose resulting motion is represented by the displacem
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3 years ago
3. How is using a model to study cells helpful?
4vir4ik [10]

Answer:

Yes, it is very helpful.

Explanation:

It's helpful since in a cell, plant or animal, there are a lot of different things. It's hard to memorize everything and know what they look like. Using a model can help you memorize everything better and even understand it better. If someone asked me where or what something was in a cell I think I would be able to recognize it better.

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6 0
3 years ago
A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe
notsponge [240]

Answer:

Q = \frac{0.068}{E}

where E = electric field intensity

Explanation:

As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical

So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field

while weight of the ball is vertically downwards

so here we have

QE = F_x

mg = F_y

since string makes 30 degree angle with the vertical so we will have

tan\theta = \frac{F_x}{F_y}

tan30 = \frac{QE}{mg}

Q = \frac{mg}{E}tan30

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Q = \frac{0.068}{E}

where E = electric field intensity

5 0
3 years ago
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