Question

Find the equation of a line that passes through the point (3,4) and has a gradient of 4.

Answer 1

Answer:

The equation of a line in the slope-intercept form is:

y = 5x - 18

The slope-intercept form of the line equation

where

   m is the slope

   b is the y-intercept

In our case, we are given

   m = 5

   Point (4, 2)

now substituting m = 5 and (4, 2) in the slope-intercept form of the line equation to determine the y-intercept

y = mx + b

2 = 5(4) + b

20 + b = 2

subtract 20 from both side

20 + b - 20 = 2 - 20

b = -18

now substituting b = -18 and m = 5 in the slope-intercept form of the line equation

y = mx + b

y = 5x + (-18)

y = 5x - 18

Therefore, the equation of a line in the slope-intercept form is:

y = 5x - 18

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Answer 2

Answer:

Step-by-step explanation:

m = 4

y = mx +c

y= 4x + c

Plugin x = 3 and y= 4 in the above equation

4 = 4*3 + c

4 = 12 +c

4 - 12 = c

c = -8

Equation of the line :

y = 4x - 8