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Fofino [41]
3 years ago
8

If you built a model of the Empire State Building that is proportional to the real building. The height of the Empire State Buil

ding is 1,250 feet. If the scale of your model is 1 inch = 50 feet how tall is your model?
Mathematics
1 answer:
tangare [24]3 years ago
7 0
Let’s see now, there are 600 inches in 50 feet.
12in = 1ft, 12in * 50 = 600.
Which means the model you’ll be making will be a 1:600 ratio model. If we find out how many inches are in 1,250 feet, and divide that number by 600, we will get our answer.
1,250 * 12 = 15,000.
So 1,250 feet equate to 15,000 inches. Now we must divide 15,000 by 600.
15,000 ÷ 600 = 25.
So your model will be 25 inches (or 2’1” [2 feet & 1 inch] tall).
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What is the slope of the line x=-3
mote1985 [20]

x = 3 is  a vertical line that goes straight up and down at 3 on the x axis, vertical lines have a undefined slope.  Don't confuse that with no slope which is a flat like like y=7.  

so the slope is undefined

4 0
3 years ago
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Nurse Jackson examines immunization records for this past winter at the school where she works. Got flu Didn't get flu Total Vac
Harman [31]

Answer:

140

Step-by-step explanation:

ap3x

6 0
3 years ago
Given: AC and AE are common external tangents of G and D. BC= 123 GB=20 and AG=101. What is the measure of AC?​
Solnce55 [7]

Answer:

The length of AC is 222 units.

Step-by-step explanation:

Given AC and AE are common external tangents of G and D.

BC= 123 ,  GB=20 and AG=101.

We have to find the measure of AC.

As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,

In ΔABG, by Pythagoras theorem

AG^2=AB^2+BG^2

⇒ 101^2=AB^2+20^2

⇒ AB^2=10201-400=9801

⇒ AB=99 units.

Hence, AC=AB+BC=99+123=222 units.

The length of AC is 222 units.

8 0
3 years ago
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
4 years ago
Multiply the sum of -13/8 and 5/12 by their difference.​
REY [17]

Answer:

1421/576

Step-by-step explanation:

Sum = - 13/8 + 5/12 = - 39/24 + 10/24 = - 29/24

Difference = - 13/8 - 5/12 = - 39/24 - 10/24 = - 49/24

Sum * Difference = (-29/24)*(-49/24) = 1421/576

6 0
2 years ago
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