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2 years ago

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A 9 pound bag of seed holds 3 pounds less than four smaller bags of seed find the weight of the smaller bag of seed

1 answer:

frosja888 [35]2 years ago

4 0

Answer:

This is a simple question for simple answer

9/3=3

3 seeds

Step-by-step explanation:

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If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

at a sport banquett 8 guests are seated at each of the 15 tables how many guests (x) are seated at the table

Novosadov [1.4K]

Answer:

120

Step-by-step explanation:

15x8=120 so that the answer

7 0

3 years ago

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Which of the following equations show how you would solve for mass if you knew the force acting on an object and the acceleratio

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The answer is d. m=f - a

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3 years ago

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Solve for x:<br> 1 1/5x−2 1/3<1/7x+1 1/2

Mashcka [7]

Answer: $x$

Step-by-step explanation:

$1\frac{1}{5}x-2\frac{1}{3}$

Add $2\frac{1}{3}$ on both sides and subtract $\frac{1}{7}x$ on both sides to leave x's on the left side and independent values on the right.

$(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}$

$1\frac{1}{5}x-\frac{1}{7}x$

Solve the fractions.

$1(\frac{1}{5}-\frac{1}{7})x$

$1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x$

$1(\frac{7-5}{35} )x$

$1(\frac{2}{35} )x$

$1\frac{2}{35}x$

Convert the mixed fraction $1\frac{2}{35}$ to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

$\frac{37}{35}x$

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

$(\frac{35}{37}) (\frac{37}{35})x$

$x$

$x$

$x$

5 0

3 years ago

3/4 of what equals 75

nignag [31]

100
75 times 1.333333333333333 equals 100

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3 years ago

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