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frutty [35]
3 years ago
14

Which of the tests would involve a chemical change in the mineral?

Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0

hmmm water

Explanation:

Water can change if you put food coloring

in it

You might be interested in
What is the structure for a-d glucose
Virty [35]

alpha-D-Glucose | C6H12O6 - PubChem. is the abswer

8 0
3 years ago
What is the index of hydrogen deficiency of a compound with a molecular formula of c6h15n?
7nadin3 [17]

Answer:

IHD = 0

Explanation:

Given that

C₆H₁₅N

Number of carbon atoms(n) = 6

Number of hydrogen atoms(x') = 15

Number of nitrogen atoms = 1

There is nitrogen atoms then x = x' -1

The index of hydrogen deficiency given as

IHD=\dfrac{2n+2-x}{2}

So

IHD=\dfrac{2n+2-x}{2}

IHD=\dfrac{2\time 6+2-(15-1)}{2}

IHD = 0

The index of hydrogen deficiency is zero.

6 0
3 years ago
1. BaBr2(aq) + H2SO4(aq) →?<br> please balance the equation and predict the products
Andrew [12]

Answer:

BaBr2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2 HBr (aq)

Explanation:

This is a precipitation reaction: BaSO4 is the formed precipitate.

4 0
3 years ago
Relative formula mass of glucose? (C6H12O6)
Rom4ik [11]

To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:

C_{6}=6*(12.01g)=72.06g

H_{12}=12*(1.008g)=12.096g

O_{6}=6*(15.999g)=95.994g

Then you add all of them together:

72.06g+12.096g+95.994g=180.15g

Therefore, the molar weight of glucose is 180.15 grams.

3 0
3 years ago
A sample of gas has a volume of 2.36 L at a temperature of 53.00 °C. The gas sample is heated to a temperature of 139.00 °C (ass
Liono4ka [1.6K]

Answer:

The volume increases because the temperature increases and is 2.98L

Explanation:

Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:

V₁/T₁ = V₂/T₂

<em>Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.</em>

In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).

Replacing in the Charles's law equation:

2.36L / 326.15K= V₂/412.15K

<h3>2.98L = V₂</h3>

<em />

5 0
3 years ago
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