I didn't see any statements, but here are some similarities of those elements:
They all have the same number of valence electrons, they will become cations, they all will lose 2 electrons, they will behave similarly in chemical reactions, they have similar chemical properties, they all are in the alkaline earth metal family. Hope this helps! :)
A. Where the number for the concentration of H+ normally includes: times 10^#. For example, the conc. is given (or determined) as [1.00x10^-5]
It is an ideal gas therefore we can use the ideal gas equation to solve the problem. The ideal gas equation is expressed as PV = nRT. First, we solve the amount of the gas in moles using the said equation and the first conditions.
(2.0 atm) (5.0 x 10^3 cm^3) = n (82.0575 atm.cm^3/mol.K)(215 K)
n=0.5668 mol
Using the second conditions given, we obtain the new pressure.
P (4.0 x 10^3) = 0.5668 x <span>82.0575 x 265
P= 3.08 atm</span>
Answer:
Two (2) types of ions
Explanation:
Metal ions (cations) and negatively charged ions (anions) of either chloride, carbonate, sulphides or hydroxides are present during the selective precipitation.
Majorly, the process determines the metal ions present by initiating precipitation as certain conditions.
I hope this was helpful.
There are <em>three</em> possibilities:
synthesis
redox (reduction/oxidation)
endothermic
