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AnnZ [28]
3 years ago
8

What two things are conserved in a chemical reaction?

Chemistry
1 answer:
Sloan [31]3 years ago
3 0
Mass and atoms are the properties conserved in every ordinary chemical reaction.

Hope this helps!
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Calculate the molecular weight when a gas at 25.0 ∘C and 752 mmHg has a density of 1.053 g/L . Express your answer using three s
stiks02 [169]

Answer:

26.0 g/mol is the molar mass of the gas

Explanation:

We have to combine density data with the Ideal Gases Law equation to solve this:

P . V = n . R .T

Let's convert the pressure mmHg to atm by a rule of three:

760 mmHg ____ 1 atm

752 mmHg ____ (752 . 1)/760 =  0.989 atm

In density we know that 1 L, occupies 1.053 grams of gas, but we don't know the moles.

Moles = Mass / molar mass.

We can replace density data as this in the equation:

0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K

(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x

0.0405 mol = 1.053 g / x

x =  1.053 g / 0.0405  mol = 26 g/mol

7 0
4 years ago
If the concentration of the product NH3 was increased from 1.0 x 10-4 M to 5.6 x 10-3 M, calculate the reaction quotient (Q) and
loris [4]

The chemical system will shift to the left in order to produce more N₂ , H₂.

The missing data in the question is

The equilibrium constant (K) of the reaction below is K = 6.0 x 10⁻² with initial concentrations as follows: H₂ = 1.0 x 10⁻² M, N₂ = 4.0 M, and NH₃ = 1.0 x 10⁻⁴M.

<h3>What is Chemical Equilibrium?</h3>

When the rate of forward reaction is equal to the rate of the backward reaction then the equation is said to be in Chemical Equilibrium.

N₂ + 3H₂ --> 2NH₃

The reaction quotient, Q, has the same algebraic expressions but uses the actual concentrations of reactants.

[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M

Thus, for the reaction:

N₂ + 3H₂ ⇄ 2NH₃

The equilibrium constant, K, of this reaction, is defined as:

\rm K = \dfrac{[NH_3]^2}{[H_2]^3 [N_2]}

\rm Q = \dfrac{[NH_3]^2}{[H_2]^3 [N_2]}

Q = (5.6 x 10⁻³ )² / (1.0 x 10⁻²) ³(4.0 )

Q = 7.84

As Q > K,

The chemical system will shift to the left in order to produce more N₂ , H₂

To know more about chemical equilibrium

brainly.com/question/4289021

#SPJ1

3 0
2 years ago
What category is most of the elements part of
rjkz [21]

Answer:

transition metals

Explanation:

they're the elements in yellow in the picture

6 0
3 years ago
The broadest taxonomic group for classifying living organisms is the blank
zloy xaker [14]

Answer:

Domain

Explanation:

5 0
3 years ago
Can someone help me? I don't know the answer and I need a justification for why the correct answer is correct
pav-90 [236]

Answer:

(A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

Step-by-step explanation:

   N₂O₄      ⇌       2NO₂

colourless      reddish-brown

NO₂ is a reddish-brown gas, while N₂O₄ is colourless.

When you cooled the sample to 0 °C, the position of equilibrium shifted to form more N₂O₄, that is, it <em>shifted to the left</em>.

According to <em>Le Châtelier's Principle,</em> when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

You applied a stress: you removed heat from the system. It responded by shifting in the direction that produces more heat (<em>to the left</em>).

If you consider heat as part of the reaction, the equation must be

N₂O₄ + heat ⇌ 2NO₂

The reaction is endothermic.

Furthermore, since the position of equilibrium shifted in the direction of reactants, the equilibrium constant decreased.

The value of K <em>decreases as the temperature decreases</em>. If we say it the other way, the value of K increases as the temperature increases.

The correct answer is (A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

(B) and (D) are <em>wrong</em>, because the reaction is endothermic.

(C) is <em>wrong</em>, because the value of Kc decreases as temperature decreases.

7 0
3 years ago
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