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Kipish [7]
2 years ago
5

Consider the following voltaic cell:(b) In which half-cell does oxidation occur?

Chemistry
1 answer:
damaskus [11]2 years ago
6 0

At the anode, half-cell oxidation occurs in a voltaic cell.

<h3>Voltaic Cell Principle</h3>

A voltaic cell generates electricity due to the Gibbs free energy of spontaneous redox processes occurring inside the cell, which is the basis for the voltaic cell's operating principle.

Two half-cells plus a salt bridge make up the voltaic cell. An electrolyte-immersed metallic electrode is present on each side of the cell. These two half-cells are wired together to form a connection to a voltmeter.

<h3>Voltaic Cell Parts</h3>
  • Copper makes comprises the cathode of a photovoltaic cell. This electrode serves as the cell's positive terminal, where reduction takes place.
  • Anode: Zink metal makes up this electrode. It creates the cell's negative electrode, where oxidation takes place.
  • Oxidation and reduction are divided into two discrete parts in two half-cells.
  • Salt Bridge: It contains the electrolytes needed to finish the circuit in the voltaic cell.
  • The flow of electrons between the electrodes occurs via the external circuit.

Learn more about Voltaic cells here:-

brainly.com/question/27908270

#SPJ4

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A pH scale reading 13 indicates a ______
lukranit [14]

Answer:

A pH scale reading 13 indicates a strong base.

Explanation:

From my understanding:

1 -4 is a strong acid

4 - 7 is weak acid

7 - 9 is a weak base

9 - 14 is a strong base

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2 years ago
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Having done the experiment, explain briefly how the mass of zinc not equal the mass of lead gained (hint: the periodic table)
masya89 [10]

Answer:

Due to the difference in the relative atomic masses and therefore, the molecular masses of Zn and Pb, one mole of Zn is about 3.2 times lighter than one mole of Pb

Explanation:

From the periodic table, we have;

The atomic number of zinc, Zn = 30

The atomic mass of zinc, Zn = 65.38 amu

The molar mass of zinc, Zn = 65.38 g/mol

The atomic number of lead, Pb = 82

The atomic mass of lead, Pb = 207.2 amu

The molar mass of lead, Pb = 207.2 g/mol

Therefore, whereby equal number of moles of Zn is lost and Pb is gained, we have;

Mass of 1 mole of Zn = 65.38 grams

Therefore, 1 gram of Zn = 1/65.38 moles = 0.0153 moles

0.12 grams of Zn = 0.12×0.0153 = 0.00184 moles of Zn

Given that equal number of moles of Zn and Pb are involved in the reaction, the number of moles of Pb gained = 0.00184 moles

The mass of Pb gained = Number of moles of Pb gained × Molar mass of Pb

The mass of Pb gained = 0.00184 × 207.2 = 0.38 g ≈ 0.4 g.

Amount of Pb gained = 0.43 g ≈ 0.4 g

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andrew11 [14]

hellow! how r you? 。◕‿◕。

Explanation:

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Calculate the number of moles of gas in the following at STP: 45.6 L of H2 gas
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45.6 L of H2 *    (1 mole of H2 / 22.4 L ) =  2.04 mol

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