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Annette [7]
3 years ago
7

I do this do y'all can get extra point and complete challenges! What is 4 + 4

Mathematics
2 answers:
mars1129 [50]3 years ago
5 0
The answer is walmart
Elina [12.6K]3 years ago
3 0

8 is the correct answer. By the way, Thank you for the few extra points.. It is very appreciated.

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WILL MARK BRAINLIEST
mafiozo [28]

Answer:

0.21

Step-by-step explanation:

36%= .36

11/25= .44

4 0
3 years ago
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HELP ME PLEASE
Mashutka [201]

Answer:

9 + \frac{n}{3} - 6 = 7

Step-by-step explanation:

Given

9 + \frac{n}{3} - 6

Required

Evaluate when n = 12

Substitute 12 for n in 9 + \frac{n}{3} - 6

9 + \frac{n}{3} - 6 = 9 + \frac{12}{3} - 6

Simplify the fraction

9 + \frac{n}{3} - 6 = 9 + 4 - 6

9 + \frac{n}{3} - 6 = 7

4 0
3 years ago
One term of (x+y)^m is 31,824x^18y^11<br> What is the value of m ?
alisha [4.7K]

Answer: The value of m is 29.

Step-by-step explanation:

Given that, One term of (x+y)^m is 31,824x^{18}y^{11}  ...(i)

We know that that (r+1)th term in (a+b)^n is given by :-

T_{r+1}=^nC_ra^{n-r}b^r  ...(ii)

On comparing (i) with (ii) , we get

a= x \text{ and } b= y \\n-r =18 \text{ and }  r=11\\n=m

i.e.

m-r=18\Rightarow\ m-11=18\\\\\Rightarrow\ m=18+11=29

Hence, the value of m is 29.

7 0
3 years ago
Evaluate ƒ(x) when x = 10
AlladinOne [14]

Answer:

10f ?

Step-by-step explanation:

fx10

8 0
3 years ago
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Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

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3 years ago
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