Answer:
Molality = 0.0862 mole/kg
Explanation:
Molality = (number of moles of solute)/(mass of solvent in kg)
Number of moles of solute = (mass of Creatinine in the blood sample)/(Molar mass of Creatinine)
To obtain the mass of creatinine in 10 mL of blood. We're told that 1 mg of Creatinine is contained in 1 decilitre of blood.
1 decilitre = 100 mL
1 mg of Creatinine is contained in 100 mL of blood
x mg of Creatinine is contained in 10 mL of blood.
x = (1×10/100) = 0.1 mg = 0.0001 g
Molar mass of Creatinine (C₄H₇N₃O) = 113.12 g/mol
Number of moles of Creatinine in the 10 mL blood sample = (0.0001/113.12) = 0.000000884 moles
Mass of 10 mL of blood = density × volume = 1.025 × 10 = 10.25 mg = 0.01025 g = 0.00001025 kg
Molality of normal creatinine level in a 10.0-ml blood sample = (0.000000884/0.00001025)
Molality = 0.0862 moles of Creatinine per kg of blood.
Hope this Helps!!!
This is genetic engineering.
I hope this helps!
Cheer,s July.
Ba stays as Ba+2 and Cl stays as Cl-
Answer:
The answer is "power dispatcher."
Explanation:
"Power dispatchers" are also known as <em>"power distributors</em>." Their field of work is related to controlling the distribution of electricity to the <em>"electrical substations." </em>These substations allow the transmission of electricity to step down from a higher voltage to a lower voltage.
Whenever there is an electrical problem, the power dispatcher also comes into play. They make sure that the power lines are intact and checks for possible damages when typhoons or earthquakes occur.
Thus, this explains the answer.
