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svlad2 [7]
3 years ago
5

A rock weighing 30.0 g is placed in a graduated cylinder displacing the volume from 22.3 mL to 27.6 mL. What is density of the r

ock in grams/cubic centimeter?
Chemistry
1 answer:
cupoosta [38]3 years ago
5 0
V'=v2-v1=27.6-22.3
density=mass/v'
ps: ml is the same as cubic cm
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Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

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\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

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Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

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The percent of dissociation of Br_2 = \alpha = 1.2 %

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The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

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