N₂ + 3H₂ ⇒ 2NH₃
1mol : 2mol
3,72mol : 7,44mol
n = 7,44mol
M = 17g/mol
m = n * M = 7,44mol * 17g/mol = 126,48g
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V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
Answer:
The net energy is 2.196 eV
Explanation:
Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.
Using:
ΔE = h*c*(1/λ
- 1/λ
)
where:
ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602*
J.
h = 4.135*
eVs
c = 3*
m/s
λ
= 300 nm = 300*
m
λ
= 640 nm = 640*
m
Thus:
ΔE = 4.135*
eVs*3*
m/s*(
)
ΔE = 4.135*
*3*
*1.77*
eV = 2.196 eV