Question

When the compound BaCl2 forms , what happens to the Ba and Cl ions

Answer 1

Ba stays as Ba+2 and Cl stays as Cl-

Answer 2

Answer : The correct answer is Ba²⁺ and Cl⁻ ions .

This can be explained using Solubility concept .

Solubility is defined as property referring to ability of a substance , SOLUTE , to dissolves in a SOLVENT . It is measured at maximum amount of solute that dissolves in solvent as equilibrium .

Solubility of any compound can be checked using Solubility Rule ( Image ).

BaCl₂ is salt of Chloride . Since the solubility rules says that salts if chlorides are soluble , Hence BaCl₂ is also soluble .

SO when BaCl₂ forms in aqueous solution , it again dissociates to forms ions since it is soluble in aqueous solution . It produced one Ba²⁺ ion and two ions of Cl⁻ .

The BaCl₂ dissociates as follows :

$BaCl_2 (aq) \rightarrow Ba^2^+ (aq) + 2 Cl^- (aq)$

Hence even BaCl₂ forms but it remain as dissociated ionic form as Ba²⁺ and Cl⁻ ions.