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2 years ago

When the compound BaCl2 forms , what happens to the Ba and Cl ions

Chemistry

2 answers:

Korvikt [17]2 years ago

6 0

Ba stays as Ba+2 and Cl stays as Cl-

Anna007 [38]2 years ago

4 0

Answer : The correct answer is Ba²⁺ and Cl⁻ ions .

This can be explained using Solubility concept .

Solubility is defined as property referring to ability of a substance , SOLUTE , to dissolves in a SOLVENT . It is measured at maximum amount of solute that dissolves in solvent as equilibrium .

Solubility of any compound can be checked using Solubility Rule ( Image ).

BaCl₂ is salt of Chloride . Since the solubility rules says that salts if chlorides are soluble , Hence BaCl₂ is also soluble .

SO when BaCl₂ forms in aqueous solution , it again dissociates to forms ions since it is soluble in aqueous solution . It produced one Ba²⁺ ion and two ions of Cl⁻ .

The BaCl₂ dissociates as follows :

$BaCl_2 (aq) \rightarrow Ba^2^+ (aq) + 2 Cl^- (aq)$

Hence even BaCl₂ forms but it remain as dissociated ionic form as Ba²⁺ and Cl⁻ ions.

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kkurt [141]

The hypothesis is that
the green coloration of plants is related to sunlight exposure of leaves
The hypothesis is tested by keeping a dark green plant inside a dark closet
The result is that the green coloration faded
The conclusion must be that exposure to sunlight affects the green color of the plants

8 0

3 years ago

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The Molar mass(M.w) in g/mol of 6.3 grams of an ideal gas that placed in 5.0 L tank at ST

BigorU [14]

Answer:

28 g/mol, N2

Explanation:

Given data:

Volume of gas = 5.0 L

Mass of gas = 6.3 g

Pressure = 1 atm

Temperature = 273 K

Molar mass of gas = ?

Solution:

We will calculate the density first.

d = mass/ volume

d = 6.3 g/ 5.0 L

d = 1.26 g/L

Molar mass:

d = PM/RT

M = dRT/P

M = 1.26 g/L× 0.0821 atm.L/mol.K × 273 K/ 1 atm

M = 28 g/mol

Molar mass of N₂ is 28 g/mol thus given gas is N₂.

7 0

2 years ago

Help it’s due right now I will give you 15 points or more

cupoosta [38]

Answer:

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3. Heat is the form of energy that is transferred between systems or objects with different temperatures.

4. Air temperature near or over bodies of water is much different from that over land due to differences in the way water and land heat and cool. Properties that affect water temperature are transparency, ability to circulate, and specific heat.

5. Radiation is the transfer of heat energy through space by electromagnetic radiation.

6. Radiation is natural and found everywhere, it comes from outer space, the air we breathe, and the earth we tread.

7. When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along. The fluid above a hot surface expands, becomes less dense, and rises.

8. Convection currents in the Earth occur in the mantle

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- Hope this helps!

5 0

2 years ago

What is the molar solubility in water of ag2cro4 ? (the ksp for ag2cro4 is 8 x 10-12. )

nikitadnepr [17]

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

<h3>How do you define Solubility ?</h3>

The measure of the degree to which a substance gets dissolved in a solvent to become a solution.

The formula for determination of molar solubity is

$\rm K_{sp} = [A^+]^a [B^-]^b$

$\rm K_{sp}$ = solubility product constant

$\rm [A^+]^a$ = cation in an aqueous solution

$\rm [B^-]^b$ = anion in an aqueous solution

a, b = relative concentrations of a and b

We have the data given as

$\rm K_{sp}$ for Ag₂CrO₄ is 8 x 10⁻¹²

For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.

We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.

Then for a saturated solution, we have

[Ag⁺]=2S

[CrO₂⁴⁻]=S

the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

(2S)²(S)=4S³ = 8 * 10⁻¹²

S=∛ (2*10⁻¹²)

S= 1.26 * 10⁻⁴ M

2S = 2.52 * 10⁻⁴ M

Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

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4 0

1 year ago

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An aqueous solution of a certain chemical is found to boil at 104.5 oC. At what temperature is this solution likely to freeze? T

xeze [42]

Answer:

16.4 °C

Explanation:

Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.

Using the ebullioscopic constant,

ΔT = m * i * Kb

Where,

Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i

Kb is the ebulliscope factor of water = 0.510 °C.kg/mol

i is the van hoffs number = 1

m is the molality in mol/kg.

Calculating the molality of the solution,

Temp.i = 100°C

Temp.f = 104.5 °C

= 4.5/(1*0.510)

= 8.8235 mol/kg

Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.

Using the same equation, but kf = 1.86 °C.kg/mol

ΔT = m * i * Kf

Temp.i = freezing point of water = 0°C

Temp.f = (8.8235*1.86) - 0

= 16.412 °C

Freezing point of the solution = 16.4 °C

3 0

2 years ago