It’s 4 I think sorry if I’m wrong
Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Since the perimeter is the sum of the length of all sides we multiply width and length by 2 and then add them together
Answer:
y= 
Step-by-step explanation:
switch the x and y and solve for y.
Answer:

Step-by-step explanation:
We have been given a graph of the function f(x).
Now we need to use that graph to find the equation of the graph and match with the correct choice from the give choices:




We see that graph has end points in opposite direction then the degree of polynomial must be ODD.
Available degrees are 3 and 4. Degree 3 is odd so it is choice B or C.
Only
satisfies the given points from graph.
Hence correct choice is
.