You just need to make a completebox and to complete boxes by adding what you know together. By doing this you can get 1120
Answer:
1- 5 to the 2nd power=25 / 25-11=14 / 14+2=16 /16+8=24
3- 6 to the 3rd power= 216/ 216-9= 207/207+1=208/ 208+4+8=220
4- 6-3=3/ 3x9=27/ 3x-9= -27/ -27+27=0
Step-by-step explanation:
I can't do all of them cuz im in 5th G but i can help u wit some
sorry i can tell this is very overwhelming also i'm am also sorry if this is wrong if this is not for work and your just practicing (thank god).
have a great day
Given:
Universal set is all positive integers {1,2,3...}
Set A is the set of all positive <u>ODD</u> integers {1,3,5,7...}
The question asks us to find , which is the <em>complement of set A</em>. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.
It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.
ANSWER: "{x|x ∈ U and is an even positive integer}"
Answer:
x = 1.125 AKA x = 1 1/8 AKA x = 9/8
Step-by-step explanation:
CB to ED = 1 : 9
Scale Factor = 1/9
-> cross multiply
9x = x + 9
-x -x
8x = 9
x = 9/8