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Finger [1]
3 years ago
13

Does clearing your hard drive make your computer faster reddit

Computers and Technology
1 answer:
kondaur [170]3 years ago
4 0
Well I suppose it would depend on what you have on your hard drive. If you have background applications that are using the computers memory without your knowledge, a clear drive would result in your performance improving. So I would say in general, clearing your drives would indeed make your computer faster. 
You might be interested in
Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 3
Katarina [22]

Answer:

The code is as follows:

for(int j = 0; j < newScores.length-1; j++){  

               newScores[j] = oldScores[j+1];  

           }  

           newScores[oldScores.length-1] = oldScores[0];

Explanation:

This loop iterates through the elements of oldScores

for(int j = 0; j < newScores.length-1; j++){  

This enters the elements of oldScores to newScores starting from the element at index 1

               newScores[j] = oldScores[j+1];  

           }  

This moves the first element of index 0 to the last index of newScores

           newScores[oldScores.length-1] = oldScores[0];

7 0
3 years ago
"Consider yourself driving with 60 miles/hour in a city that has only grid like streets, and your GPS is broken.The specificatio
timama [110]

Answer:

see explaination

Explanation:

// Include the necessary header files.

import java.io.*;

import java.util.Random;

import java.lang.Math;

// Declare a class

public class GPS

{

// Definition of the function.

public static int randSel(int start, int fin)

{

// Declare the object of a class.

Random r = new Random();

// Declare an integer value and store

// value in it.

int rNum = r.nextInt((fin - start) + 1) + start;

// return value.

return rNum;

}

// Definition of the function.

public static double DistFromOrig(double X, double Y)

{

// Declare a double variable.

double dist;

// Calculate the distance.

dist = Math.sqrt(X * X + Y * Y);

// return distance.

return dist;

}

// Start the main method.

public static void main(String[] args)

{

try

{

// declare variables

double X = 0, Y = 0;

int time = 60;

final int NORTH = 0;

final int EAST = 1;

final int SOUTH = 2;

final int WEST = 3;

int Direction = 0;

// Start the while loop

while (time > 0)

{

// check whether the time is greater

// than 5 or not.

if (time >= 5)

{

// update the value of time.

time -= 5;

// call to the method.

Direction = randSel(0, 3);

if (Direction == NORTH)

{

// update the value of y cordinate.

Y = Y + 5;

// display the statement on console.

System.out.println("MOVED NORTH");

}

// Check the direction

if (Direction == EAST)

{

// update the value of x cordinate.

X = X + 5;

// display the statement on console.

System.out.println("MOVED EAST");

}

// Check the direction

if (Direction == WEST)

{

// update the value of x cordinate.

X = X - 5;

// display the statement on console.

System.out.println("MOVED WEST");

}

// Check the direction

if (Direction == SOUTH)

{

// update the value of y cordinate.

Y = Y - 5;

// display the statement on console.

System.out.println("MOVED SOUTH");

}

}

else

{

// Check the direction

if (Direction == NORTH)

{

// update the value of y cordinate.

Y = Y + time * 1;

time = 0;

}

// Check the direction

if (Direction == EAST)

{

// update the value of x cordinate.

X = X + time * 1;

time = 0;

}

// Check the direction

if (Direction == WEST)

{

// update the value of x cordinate.

X = X - time * 1;

time = 0;

}

// Check the direction

if (Direction == SOUTH)

{

// update the value of y cordinate.

Y = Y - time * 1;

time = 0;

}

}

}

// Display the statement on console.

System.out.println(

"Distance of Car After Traveling 1 Hr is "

+ DistFromOrig(X, Y)

+ " miles");

}

// Start the catch block.

catch (Exception e)

{

e.printStackTrace();

}

}

}

4 0
3 years ago
. Alex discovered a bunch of SATA drives in a box at the office and needs to check the contents. What can he do so that Windows
ZanzabumX [31]

You have to make sure the BIOS boot is set to the normal hard drive first, then plug in the SATA cable and power properly

8 0
3 years ago
Convert the following numbers from decimal to binary, assuming unsigned binary representation:________.
kumpel [21]

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\  2 & 17 & 1 \\   2 & 8 & 0  \\ 2 & 4 & 0  \\ 2 & 2 & 0   \\ 2 & 1 & 1\end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\  2 & 1 & 1 \\  \end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\  2 & 13 & 1 \\   2 & 6 & 0  \\ 2 & 3 & 1  \\ 2 & 1 & 1   \end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\  2 & 8 & 0 \\   2 & 4 & 0  \\ 2 & 2 & 0  \\ 2 & 1 & 1   \\\end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = <em>100011</em>

B) 3 = <em>11</em>

C) 27 = <em>11011</em>

D) 16 = <em>10000</em>

8 0
3 years ago
A short cut to save a file is
Vanyuwa [196]

Answer:

CTRL+S in most programs

8 0
2 years ago
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