All categories

3 years ago

G(x) = { 0 – 3; g(x) = -4

Mathematics

1 answer:

Lisa [10]3 years ago

6 0

Answer:

g(x) = { 0 – 3; g(x) = -4

Step-by-step explanation:

g(x) = { 0 – 3; g(x) = -4

You might be interested in

Solve x/2 - 3 = 7. 5 10 20 40

earnstyle [38]

<span> x/2 - 3 = 7
Add 3 to both sides
x/2=10
Multiply 2 on both sides
Final Answer: B. 20</span>

3 0

3 years ago

Read 2 more answers

Please help! 20 points!

MakcuM [25]

12/3 = 4

it was dilated with a scale factor of 4

6 0

4 years ago

Me pueden ayudar profabor

Svet_ta [14]

Answer:

que que

Step-by-step explanation:

que

4 0

3 years ago

A rock dropped on the moon will increase its speed from 0 m/s (its starting

belka [17]

<h2>Hello!</h2>

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!

7 0

3 years ago

Drag the simplified value into the box to match each expression.

Mama L [17]

Answer:

4^0 + 2 x 3 - 2 = 5

2^2 + 10 - 3 x 2 = 8

9 + 3^2 - 1 x 4 = 14

please give brainliest

5 0

3 years ago