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son4ous [18]
3 years ago
14

Which postulate or theorem proves the triangles below are congruent?

Mathematics
2 answers:
nignag [31]3 years ago
7 0

       SAS - We have two sides (the small lines indicate this) and the angles across from each other (vertical angles) are congruent. This means the triangles are proven congruent by the SAS Congruence Postulate.

       Knowing this, we can say that AAS and ASA also apply, but as it is not known until we have SAS, I believe SAS is the only "correct" answer.

(HL does not apply here as we do not have right-triangles)

Have a nice day! :)

frosja888 [35]3 years ago
6 0

Answer:

he

Step-by-step explanation:

he

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Marcus spends $58 at the bookstore. He spends the same amount of money on each of the 4 books he purchase. He also paid $4 in sa
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Answer:

$15.5

Step-by-step explanation:

58+4=62 62divided by4=15.5 :) Have a nice day

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WILL MARK BRAINLEST, HELP W/ MATH QUESTION !!!
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Answer:

The average rate of change is 0

Step-by-step explanation:

You don't really have to do any math for this problem. The vertex lies at the center of [-2,11] so it means that the slope going across the interval line (x=1) is 0. (i used desmos to graph it)

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4 0
3 years ago
Maya made $324 for 18 hours of work. At the same rate how many hours would she have to work to make $126
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3 years ago
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-(m-3)=5m-(6m-7)-4 solve?
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Answer:

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4 0
3 years ago
You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu
stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}

C=3\pi r^{2}+ \frac{162 \pi}{r}

We differentiate C with respect to r

C'=6\pi r -\frac{162 \pi}{r^2}

At the minimum cost, C'=0.

Next we solve C'=0 for r

6\pi r -\frac{162 \pi}{r^2}=0

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0
4 years ago
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