No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
If you would like to expand and simplify 3 * (x + 2) + 2 * (x - 1), you can do this using the following steps:
3 * (x + 2) + 2 * (x - 1) = 3 * x + 3 * 2 + 2 * x - 2 * 1 = 5 * x + 6 - 2 = 5 * x + 4
The correct result would be 5 * x + 4.
Answer:
Answers in the pics
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask ÷)
