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dsp73
2 years ago
8

Does the point (8, 8) satisfy the equation y = x?

Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:

Yes.

Step-by-step explanation:

Substitute the values for the variables in the equation.

y = x

(8) = (8)

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There are 2 blue, 6 yellow, 10 red, 3 green, 5 orange, and 4 purple marbles in a jar. What is the probability that a red marble
seraphim [82]

Answer:

1/3

Step-by-step explanation:

sum of numbers = 30 marbles

probability = 10/30 or simplified 1/3

6 0
2 years ago
For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?
Gre4nikov [31]

The equation is separable, so solving it is trivial:

\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt

Integrating both sides gives

\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}

Given y(0)=24 and y(1)=18, we find

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so the answer is E.

8 0
3 years ago
Read 2 more answers
to mail a cardboard box, you measure its size and mass. It is 55cm long , 25cm wide and 20 cm high. The mass of the box is 4kg.
ch4aika [34]

Answer:

Density is usually expressed as grams per cubic centimeter.

Volume = 55 * 25 * 20 = 27,500 cc

Density = Mass / Volume = 4,000 grams / 27,500 cc

= 0.1454545455 grams/cc

which is an extremely low density


Step-by-step explanation:


8 0
3 years ago
(1,1),(-1,0)<br> 2x+y=3<br> X-2y=-1<br> Each pair of a solution of the system of linear equations
kotykmax [81]
Is there a photo with this
7 0
3 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
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