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sertanlavr [38]
3 years ago
6

Help My please………………….

Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer: don't know sorry

Explanation:

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If a bit is travelling through a copper wire at 2 x 10 8 meters per second, how far does it go in a millisecond?
zavuch27 [327]

Answer:

2\times10^5m

Explanation:

1 second = 1000 millisecond, so if within 1 second a bit could travel a distance of 2\times10^8m through a copper wire then within a millisecond (a thousandth of a second) it should be able to travel through a distance of

\frac{2\times10^8}{1000} = 2\times10^5m

3 0
4 years ago
Describe the core-mantle-crust structures of the terrestrial worlds. What is differentiation? What do we mean by the lithosphere
Serhud [2]

Answer:

The core: this structure of the terrestrial world is made up of sulphur, iron, silicon and it is found at the centre of the terrestrial world.

The mantle: this structure of the terrestrial world is located between the outer core and the crust and consist of mainly silicate rock.

The crust: this is the structure of the terrestrial world that makes up the outermost layer. It consist of granite and basalt.

Differentiation: this is the process by which gravity separates materials according to density, with high-density materials sinking and low-density materials rising.

Lithosphere: this is made up of the hard and rigid outer layer of the terrestrial planet and it's located between the crust and the outermost mantel.

The five terrestrial worlds includes Mercury, Venus, Earth, the Moon, and Mars. The largest which includes the Venus and Earth has the thinnest lithosphere while the smallest ( mercury and moon) have the thickest lithosphere.

8 0
4 years ago
Plz I need help with number 1 !!!
Darya [45]
Speed-up
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5 0
3 years ago
An astronaut notices that a pendulum which took 2.45 s for a complete cycle of swing when the rocket was waiting on the launch p
klio [65]

Answer:

2.84 g's with the remaining 1 g coming from gravity (3.84 g's)

Explanation:

period of oscillation while waiting (T1) = 2.45 s

period of oscillation at liftoff (T2) = 1.25 s

period of a pendulum (T) =2π. \sqrt{\frac{L}{a} }

where

  • L = length
  • a = acceleration

therefore the ration of the periods while on ground and at take off will be

\frac{T1}{T2} =(2π \sqrt{\frac{L}{a1} } ) /  (2π\sqrt{\frac{L}{a2} })

where

  • a1 = acceleration on ground while waiting
  • a2 = acceleration during liftoff

\frac{T1}{T2} = \frac{\sqrt{\frac{L}{a1} }}{\sqrt{\frac{L}{a2} }}

squaring both sides we have

(\frac{T1}{T2})^{2} = \frac{\frac{L}{a1} }{\frac{L}{a2} }

(\frac{T1}{T2})^{2} = \frac{a2}{a1}

assuming that the acceleration on ground a1 = 9.8 m/s^{2}

(\frac{T1}{T2})^{2} = \frac{a2}{9.8}

a2 = 9.8 x (\frac{T1}{T2})^{2}

substituting the values of T1 and T2 into the above we have

a2 = 9.8 x (\frac{2.45}{1.25})^{2}

a2 = 9.8 x 3.84

take note that 1 g = 9.8 m/s^{2} therefore the above becomes

a2 = 3.84 g's

Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.

5 0
4 years ago
Select all of the ways collection areas use to gain water.
Vedmedyk [2.9K]

Answer:

runoff from precipitation

precipitation falls direction into the collection area

Explanation:

i took the test

4 0
3 years ago
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