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liberstina [14]
4 years ago
15

Describe the core-mantle-crust structures of the terrestrial worlds. What is differentiation? What do we mean by the lithosphere

? How does lithospheric thickness vary among the five terrestrial worlds?
Physics
1 answer:
Serhud [2]4 years ago
8 0

Answer:

The core: this structure of the terrestrial world is made up of sulphur, iron, silicon and it is found at the centre of the terrestrial world.

The mantle: this structure of the terrestrial world is located between the outer core and the crust and consist of mainly silicate rock.

The crust: this is the structure of the terrestrial world that makes up the outermost layer. It consist of granite and basalt.

Differentiation: this is the process by which gravity separates materials according to density, with high-density materials sinking and low-density materials rising.

Lithosphere: this is made up of the hard and rigid outer layer of the terrestrial planet and it's located between the crust and the outermost mantel.

The five terrestrial worlds includes Mercury, Venus, Earth, the Moon, and Mars. The largest which includes the Venus and Earth has the thinnest lithosphere while the smallest ( mercury and moon) have the thickest lithosphere.

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A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w
user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"

Mathematically:

p\propto T

where

p is the gas pressure

T is the absolute temperature

For a gas undergoing a transformation, the law can be rewritten as:

\frac{p_1}{T_1}=\frac{p_2}{T_2}

where in this problem:

p_1=0.981 atm is the initial pressure of the gas

T_1=65^{\circ}+273=338 K is the initial absolute temperature of the gas

T_2=41^{\circ}+273=314 K is the final temperature of the gas

Solving for p2, we find the final pressure of the gas:

p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm

3 0
4 years ago
Finderkeepers,ismadeormodel
ankoles [38]

Answer:

model lol

Explanation:

7 0
3 years ago
Acceleration and Force
olga55 [171]

Answer:

I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .

Explanation:

15m/s - 0m/s divided by 5 s = 3m/s

I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry

6 0
2 years ago
A 25 n object requires a 5.0 n to start moving over a horizontal surface. what is the coefficient of static friction?
olganol [36]
Static friction is the friction that exists between two or more solids that are not moving with a relative speed. To calculate the static friction coefficient we use the formula Fs=us × n where Fs is the static friction , us is the coefficient of static friction and the n is the normal force.
thus the coefficient of static friction will be 5 N÷ 25 N =  0.2
Hence 0.2 is the coefficient of static friction
3 0
3 years ago
Read 2 more answers
An interference pattern is produced by light with a wavelength 580 nm from a distant source incident on two identical parallel s
irakobra [83]

Answer:

Explanation:

1 )

Here

wave length used that is λ = 580 nm

=580 x 10⁻⁹

distance between slit d = .46 mm

= .46 x 10⁻³

Angular position of first order interference maxima

= λ / d radian

= 580 x 10⁻⁹ / .46 x 10⁻³

= 0.126 x 10⁻² radian

2 )

Angular position of second order interference maxima

2 x  0.126 x 10⁻² radian

= 0.252 x 10⁻² radian

3 )

For intensity distribution the formula is

I = I₀ cos²δ/2 ( δ is phase difference of two lights.

For angular position of θ1

δ = .126 x 10⁻² radian

I = I₀ cos².126x 10⁻²/2

= I₀ X .998

For angular position of θ2

I = I₀ cos².126x2x 10⁻²/2

=  I₀ cos².126x 10⁻²

8 0
3 years ago
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