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liberstina [14]
3 years ago
15

Describe the core-mantle-crust structures of the terrestrial worlds. What is differentiation? What do we mean by the lithosphere

? How does lithospheric thickness vary among the five terrestrial worlds?
Physics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

The core: this structure of the terrestrial world is made up of sulphur, iron, silicon and it is found at the centre of the terrestrial world.

The mantle: this structure of the terrestrial world is located between the outer core and the crust and consist of mainly silicate rock.

The crust: this is the structure of the terrestrial world that makes up the outermost layer. It consist of granite and basalt.

Differentiation: this is the process by which gravity separates materials according to density, with high-density materials sinking and low-density materials rising.

Lithosphere: this is made up of the hard and rigid outer layer of the terrestrial planet and it's located between the crust and the outermost mantel.

The five terrestrial worlds includes Mercury, Venus, Earth, the Moon, and Mars. The largest which includes the Venus and Earth has the thinnest lithosphere while the smallest ( mercury and moon) have the thickest lithosphere.

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The law of conservation of mass or principle of mass conservation

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A non-_____ rock has interlocking grains with no specific pattern.
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What is the acceleration of the box?
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Answer:

a=4,32m/s^2

Explanation:

Fnet = F1 - F2

= 12-1.2

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3 years ago
In a bumper car arena, two cars of equal mass are heading straight toward each other. The orange one is traveling at a speed of
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hope this helps! ✌

4 0
2 years ago
(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th
Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

 

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

V_{f}: is the final speed = 14 m/s

V_{0}: is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m

c) The time can be found using the following equation:

V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

3 0
3 years ago
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