Can you please ask someone else
Answer:
I am going to say... B.
Step-by-step explanation:
I can't explain, it will take too long. I am not 100% sure, but I think I am correct. Please don't delete my answer, I am only trying to help.
On enlarging the rectangle, the proportion or ratio of Length to Height will stay the same.
The ratio of original length to height is 13 : 6
The ratio in enlarged rectangle will stay the same. Let the height of enlarged rectangle is y cm. So we can write:
![13:6=19.5:x \\ \\ \frac{13}{6} = \frac{19.5}{x} \\ \\ x=19.5* \frac{6}{13}=9](https://tex.z-dn.net/?f=13%3A6%3D19.5%3Ax%20%5C%5C%20%20%5C%5C%20%0A%20%5Cfrac%7B13%7D%7B6%7D%20%3D%20%5Cfrac%7B19.5%7D%7Bx%7D%20%5C%5C%20%20%5C%5C%20%0Ax%3D19.5%2A%20%5Cfrac%7B6%7D%7B13%7D%3D9%20%20)
Therefore, the height in enlarged rectangle will be 9 cm
Answer: x=3.6; y=-2.5
Step-by-step explanation:
To solve this pair of equations, we can use elimination method.
5x+4y=8
10x-4y=46
Add both equations together to cancel out 4y.
15x=54 [divide both sides by 15]
x=3.6
Now that we know x, we can plug it back into any equation to find y.
5(3.6)+4y=8 [multiply]
18+4y=8 [subtract both sides by 18]
4y=-10 [divide both sides by 4]
y=-2.5
Now, we have x=3.6 and y=-2.5.