Answer:
The moles of KClO3 = 0.052 moles
Explanation:
Step 1: Calculate the pressure of oxygen gas
The oxygen has a total pressure (including water vapour) of 760 mmHg
The pressure of Oxygen = (760 - 26) mmHg
= 734 mmHg of water vapor
Step 2: Calculate the no of moles of oxygen
Using Ideal gas equation
P V = n R T
P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas
V = 2 litres = 0.002 m3
R = gas constant = 8.31
T= 27oC = 300 K
Applying this equation P V = n R T
97,858.6 x 0.002 = n x 8.31 x 300
n = 0.0785 mol of Oxygen
From the balanced equation
2 KClO 3 ---- 2 KCl + 3 O 2
3 moles of oxygen is produced from 2 moles KClO3
so 0.0785 mole of oxygen will be produced from x
x = (0.0785 x 2 ) / 3
x = 0.052 moles of KClO3
Difference between molecular weight and molar mass
Hint : Molar mass of molecules is also called molecular weight . Its unit is gram per mole. We can calculate molar mass of molecule with the help of following rules; ... Molar mass of nitric acid (HNO3) =atomic mass of hydrogen + atomic mass of nitrogen +3× atomic mass of oxygen .
Answer: ![[Ni(NH_3)_3Br]Cl](https://tex.z-dn.net/?f=%5BNi%28NH_3%29_3Br%5DCl)
and ![[Ni(NH_3)_3Cl]Br](https://tex.z-dn.net/?f=%5BNi%28NH_3%29_3Cl%5DBr)
are ionization isomers.
![[Pt(Cl)_2(SCN)_4]^{4-}](https://tex.z-dn.net/?f=%5BPt%28Cl%29_2%28SCN%29_4%5D%5E%7B4-%7D)
and ![[Pt(Cl)_2(NCS)_4]^{4-}](https://tex.z-dn.net/?f=%5BPt%28Cl%29_2%28NCS%29_4%5D%5E%7B4-%7D)
are linkage isomers.
Explanation:
Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex
Thus and are ionization isomers.
Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.
Thus and are linkage isomers.
When a light is on, it is part of a "closed" circuit.
The rms speed of a gas can be calculated using the following rule:
Vrms = sqrt[(3RT) / M] where
R is the gas constant = 8.314 <span>J K^−1 mol^−1
T is the temperature = 32.5 + 273 = 305.5 degree kelvin
M is the molar mass = 2*14 = 28 grams = 0.028 kg
Substitute with the givens in the equation to get the rms speed as follows:
Vrms = sqrt [(3*8.314*305.5) / 0.028]
Vrms = 521.665 m/sec</span>
