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harina [27]
3 years ago
10

15. Nadia wrote the following sentence in her report on Pluto: "Pluto is a dwarf planet because it has a spherical shape

Chemistry
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

B. Pluto's orbit is not clear of other objects

Explanation:

Pluto is a dwarf planet and considered as ninth planet of the solar system.

A large body whose orbit do not clear the neighbourhood is classified as a dwarf planet. The gravity of Neptune limit the orbit of Pluto and shares its orbital neighbourhood with many Kuiper belt objects.

Hence, the correct answer is "B. Pluto's orbit is not clear of other objects".

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A sample of chemical X is found to contain 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen. The law of def
frozen [14]

Answer: 75 grams sample of chemical X should contain 21.43 grams of carbon

Explanation: The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio.

From the question, chemical X contains 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen.

Sum up the masses

5.0g + 10.0g + 20.0g = 35.0g

This means, 10.0 grams of carbon are present in 35.0 grams of chemical X.

Now, to the determine the mass of carbon that 75 gram sample of chemical X should contain,

According to the law of definite proportion, the component elements of a given chemical compound are in fixed ratio. Therefore,

If 35.0g of chemical X contains 10.0g of carbon

Then, 75 g of chemical X will contain

(75 × 10) / 35 g

= 21.43 grams

Hence, 75 grams sample of chemical X should contain 21.43 grams of carbon.

4 0
3 years ago
Read 2 more answers
What is the correct name for the following compound?<br> LIAF
laiz [17]

Answer:

the correct name is London  international animation festival

Explanation:

7 0
3 years ago
Consider the reaction of CaC2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How mu
xz_007 [3.2K]

Answer:

16.27 g  of CaCO3 are produced upon reaction of 45 g CaCN2 and 45 g of H2O.

Explanation:

Ca(CN)2 + 3H2O → CaCO3 + 2 NH3

First of all, let's find out the limiting reactant.

Molar mass Ca(CN)2.

Molar mass H2O: 18 g/m

Moles of Ca(CN)2: mass / molar mass

45 g / 92.08 g/m = 0.488 moles

Moles of H2O: mass / molar mass

45g / 18g/m = 2.50 moles

This is my rule of three

1 mol of Ca(CN)2 needs 3 moles of H2O

2.5 moles of Ca(CN)2 needs (2.5 . 3) / 1 = 7.5 moles

I need 7.5 moles of water, but I only have 0.488. Obviously water is the limiting reactant; now we can work on it.

3 moles of water __ makes __ 1 mol of CaCO3

0.488 moles of water __ makes ___ (0.488 . 1) / 3 = 0.163 moles

Molar mass CaCO3 = 100.08 g/m

Molar mass . moles = mass

100.08 g/m  .  0.163 moles = 16.27 g

4 0
3 years ago
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in
Sergio039 [100]

Answer:

  • <em>2NaCl → 2Na + Cl₂, ΔH = 822 kJ </em>

Explanation:

The chemical <em>equation</em> for the <em>formation of NaCl</em> is:

  • Na + (1/2) Cl₂ → NaCl , ΔH = - 411 kJ

That equation means that 1 mole of NaCl is formed by the reaction of 1 mole of Na and 1/2 mole of Cl₂, with a release of energy of 411 kJ.

The <em>decomposition</em> of <em>NaCl</em> is the inverse of the <em>formation</em> reaction; thus, you swift products and reactants and inverse the sign of the <em>change in enthalpy:</em>

  • NaCl → Na + 1/2 Cl₂, ΔH = 411 kJ

Since you want the decomposition of 2 moles you multiply the equation and the ΔH by 2:

  • 2NaCl → 2Na + Cl₂, ΔH = 822 kJ ← answer

3 0
3 years ago
What mass of water vapor is produced from the gas phase reaction of O2 with H2 in a 2.5 L container at 28 °C if the partial pres
Bumek [7]

Answer:2.27 g H2O

Explanation:

Step 1. Get the limiting reagent

1.24 atm of H2 would react completely with 1.24 x (1/2) = 0.62 atm of O2, but there is more O2 present than that (0.98). O2 is in excess and H2 is the limiting reactant.

If the reaction goes to completion:

(1.24 atm H2) x (2 mol H2O / 2 mol H2) = 1.24 atm H2O vapor

n = PV / RT = (1.24 atm) x (2.5 L) / ((0.08205746 L atm/K mol) x (28 + 273)K) = 0.126 mol H2O

(0.126 mol H2O) x (18.01532 g H2O/mol) = 2.27 g H2O

3 0
3 years ago
Read 2 more answers
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