Answer:
a) M HCl = 32.162 mol/L
b) m HCl = 15.873 mol/Kg
Explanation:
- wt% = (mass HCl / mass sln)×100
- δ HCl = mass HCl / Volume sln
- molarity = mol HCl / V sln (L)
- molality = mol HCl / Kg solvent
∴ MW HCl = 36.46 g/mol
assuming mass sln = 1 g
∴ mass sln = 1 g = g solvent + g solute
∴ solute: HCl
⇒ 0.37 = g HCl / g sln
⇒ g HCl = 0.37 g
⇒ g ste = 1 - 0.37 = 0.63 g
⇒ Kg ste = (0.63 g)×(Kg/1000 g) = 6.3 E-4 Kg
⇒ mol HCl = (0.37 g HCl)×(mol/36.46 g HCl) = 0.010 mol HCl
∴ V sln = (0.37 g)/(1.19 g/mL) = 0.3109 mL
⇒ V sln = (0.31 mL)×( L/1000 mL) = 3.109 E-4 L
a) molarity (M):
⇒ M HCl = 0.010 mol HCl / 3.109 E-4 L
⇒ M HCl = 32.162 mol/L
b) molality (m):
⇒ m HCl = ( 0.010 mol HCl) / (6.3 E-4 Kg)
⇒ m HCl = 15.873 mol/Kg
Answer:
The temperature remains constant because the internal energy only depends on temperature in that case
-Hops
Firstly, An ionic bond results when the sharing is so unequal that fully charged ions form. Electronegativity difference can be used to predict bond type. Secondly, one method to classify bonds based on this difference can be described as follows. If the electronegativities differ by less than 0.4 units, the bond can be classified as nonpolar covalent. If the difference is between 0.4 and 2.0 units, the bond is classified as polar covalent, and if the difference is more than 2.0 units, the bond is substantially ionic.
<h2> ║∧║······→Hello.←······║∧║</h2>
Your answer should be:
N2 + O2 → 2NO
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The total amount of water in the beaker is 0.8 Liters
calculation
convert 300 Ml in liters
that is 1 L = 1000 Ml
? = 300 Ml
by cross multiplication
1 L x300 Ml/ 1000 Ml = 0.3 Ml
total is therefore = 0.5 Ml + 0.3 Ml = 0.8 Liters