Answer:
158 in²
Step-by-step explanation:
<u>Surface area</u>
A = 2·(l·w + l·h + w·h)
= 2·(3in·8in + 8in·5in + 3in·5in)
= 2·(24in² + 40in² + 15in²)
= 2·(79in²)
= 158 in²
al3xis
Answer:
$ 31050
Step-by-step explanation:
<em>Step 1 : Write the formula for calculating simple interest.</em>
Simple Interest = <u>P x R x T </u>
100
P: Principal Amount-The loan taken (30,000)
R: Interest rate at which the loan is give (6)
T: Time period of the loan in years-there are 12 months in 1 year. There are 7 months from May till June (7/12)
<em>Step 2: Substitute values in the formula</em>
Simple Interest = <u>30,000 x 6 x 7/12</u>
100
Simple Interest = $1050
<em>Step 3: Calculate the amount due at maturity</em>
At the maturity or the end of the time period given, the original or principal amount of the loan has to be repaid along with the simple interest.
Amount at maturity = Principal Amount + Simple Interet
Amount at maturity = 30,000 + 1050
Amount at maturity = $31050
!!
Answer:
The second one.
Step-by-step explanation:
Slope intercept is rise/run. The y-axis goes up by 4 (rises by 4), and the x-axis goes to the right by 5 (runs by 5).
The expression that represents the value of z is ![\sqrt[3]{3 + i\sqrt 3 }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%20%2B%20i%5Csqrt%203%20%7D)
<h3>What are complex numbers?</h3>
Complex numbers are numbers that have real and imaginary parts
A complex number (n) is represented as:

From the above expression, we have:
- a represents the real part
- bi represents the imaginary part
Given that:

Rewrite the above expression as:

Take the cube roots of both sides
![z = \sqrt[3]{3 + i\sqrt 3 }](https://tex.z-dn.net/?f=z%20%3D%20%5Csqrt%5B3%5D%7B3%20%2B%20i%5Csqrt%203%20%7D)
The letters are not given.
Hence, the expression that represents the value of z is ![\sqrt[3]{3 + i\sqrt 3 }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%20%2B%20i%5Csqrt%203%20%7D)
Read more about complex numbers at:
brainly.com/question/11089283
Answer:
Step-by-step explanation:
Combine like terms. Like terms have same variable with same power
a) (2xy + 4x) + (15xy - 5x) = <u>2xy + 15xy</u> +<u> 4x - 5x</u>
= 17xy - x
b) (6a + 4b² - 3) + (3b² - 5) = 6a + <u>4b² + 3b²</u> <u>- 3 - 5 </u>
= 6a + 7b² - 8
c) (4x³ - 3x² +4x) + (8x² - 5x ) = 4x³ <u>- 3x² + 8x²</u> <u>+ 4x - 5x</u>
= 4x³ + 5x² - x
d) (7b - 6a + 9y) - (12b + 5a - 2y) =
In subtraction, add the additive inverse of (12b + 5a - 2y)
additive inverse = - 12b - 5a + 2y
(7b - 6a + 9y) - (12b + 5a - 2y) = 7b - 6a + 9y -12b -5a + 2y
= 7b - 12b -6a - 5a + 9y + 2y
= -5b - 11a + 11y
e) (2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)
Additive inverse of 13x + 4x² + 5 - 6y = -13x + 4x² - 5 + 6y
(2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)= 2x² + 7x - 2 + 9y -13x - 4x² -5 +6y
= 2x² - 4x² + 7x -13x -2 - 5 + 9y + 6y
= -2x² - 6x - 7 + 15y