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vladimir2022 [97]
3 years ago
15

PLS HELP ASAP ILL GIVE BRAINLIEST THANKS

Mathematics
2 answers:
monitta3 years ago
8 0

Answer:

Adding 16 on both sides

Step-by-step explanation:

The first step would be adding 16 on both sides to isolate the 5r and find the value of r

Which means you were correct, good job!

svetoff [14.1K]3 years ago
5 0
Add 16 to both side of the equation after that divide both side by 5
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By using Euler's formula, find the number of edges of a polyhedron with 16 faces and 20 vertices​
Lina20 [59]

Answer:

34 edges

Step-by-step explanation:

Euler's formula for polyhedron states

F + V - E = 2

where F is number of faces, V, number of vertices, E number of edges

Here F = 16, V = 20, thus

16 + 20 - E = 2, that is

36 - E = 2 ( subtract 36 from both sides )

- E = - 34 ( multiply both sides by - 1 )

E = 34

8 0
3 years ago
Helppp pleaseee asappp
Anna35 [415]

(a) 8:30 am

(b) 17 minutes

(c) 10:15

3 0
3 years ago
There are 6 paintings on three walls of a room. If annart gallery has 13 such rooms, how many paintings are there in its collect
SSSSS [86.1K]

Answer: (I think)

78 paintings

Step-by-step explanation:

6 x 13 = 78

3 0
4 years ago
Can anyone help? <br><br> If arcLM = 8x-56 and arcNP = 5x+22, find arcLP.
Mashcka [7]

Answer:

arcLP = 19

Step-by-step explanation:

Given the following

arcLM = 8x-56

arcNP = 5x+22

Required

arcLP

Given that arcLM = arcNP

8x-56 = 5x+22

8x - 5x  = 22 + 56

3x = 78

x = 78/3

x = 26

Let assume arcLP = x - 7

arcLP = 26 -7

arcLP = 19

4 0
3 years ago
This is a variation acitivity:
sergey [27]

\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \stackrel{\textit{\underline{I} varies jointly with \underline{P} and \underline{t}}}{I=kPt} \\\\\\ \textit{we also know that } \begin{cases} P=2000\\ t=4\\ I=320 \end{cases}\implies 320=k(2000)(4)\implies \cfrac{320}{(2000)(4)} \\\\\\ 0.04=k\qquad therefore\qquad \boxed{I=0.04Pt} \\\\\\ \textit{if P=5000 and t=7, what is \underline{I}?}\qquad I=0.04(5000)(7)\implies I=1400

8 0
3 years ago
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