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IgorC [24]
3 years ago
12

The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficienc

y of the machine?
Physics
2 answers:
notsponge [240]3 years ago
5 0
Input work = 9.63×10³ J.
Output work = 3.0×10³ J

By definition,
Efficiency = (Output work)/(Input work)
                 = (3.0×10³)/(9.63×10³)
                 = 0.31 = 31%

Answer:  31%
Elanso [62]3 years ago
3 0

Answer: The percentage efficiency of the machine is 31.15 %.

Explanation:

Input work done = 9.63\times 10^3 joules

Output work done = 3.0\times 10^3 joules

The efficiency of the machine = \frac{W_{Out}}{W_{In}}\times 100

efficiency \%=\frac{3.0\times 10^3 joules}{9.63\times 10^3 joules}\times 100=31.15\%

The percentage efficiency of the machine is 31.15 %.

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2 years ago
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Answer:

Answer:196 Joules

Explanation:

Hello

Note:  I think the text in parentheses corresponds to another exercise, or this is incomplete, I will solve it with the first part of the problem

the work  is the product of a force applied to a body and the displacement of the body in the direction of this force

assuming that the force goes in the same direction of the displacement, that is upwards

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F=mg(mass *gravity)\\F=4kgm*9.8\frac{m}{s^{2} }\\ F=39.2 Newtons\\replace\\\\W=39.2 N*5m\\W=196\ Joules

Answer:196 Joules

I hope it helps

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3 years ago
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Light rays in a material with index of refrection 1.35 1.35 can undergo total internal reflection when they strike the interface
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