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IgorC [24]
3 years ago
12

The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficienc

y of the machine?
Physics
2 answers:
notsponge [240]3 years ago
5 0
Input work = 9.63×10³ J.
Output work = 3.0×10³ J

By definition,
Efficiency = (Output work)/(Input work)
                 = (3.0×10³)/(9.63×10³)
                 = 0.31 = 31%

Answer:  31%
Elanso [62]3 years ago
3 0

Answer: The percentage efficiency of the machine is 31.15 %.

Explanation:

Input work done = 9.63\times 10^3 joules

Output work done = 3.0\times 10^3 joules

The efficiency of the machine = \frac{W_{Out}}{W_{In}}\times 100

efficiency \%=\frac{3.0\times 10^3 joules}{9.63\times 10^3 joules}\times 100=31.15\%

The percentage efficiency of the machine is 31.15 %.

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