Question

The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficiency of the machine?

Answer 1

Input work = 9.63×10³ J.
Output work = 3.0×10³ J

By definition,
Efficiency = (Output work)/(Input work)
                 = (3.0×10³)/(9.63×10³)
                 = 0.31 = 31%

Answer:  31%

Answer 2

Answer: The percentage efficiency of the machine is 31.15 %.

Explanation:

Input work done = $9.63\times 10^3 joules$

Output work done = $3.0\times 10^3 joules$

The efficiency of the machine = $\frac{W_{Out}}{W_{In}}\times 100$

$efficiency \%=\frac{3.0\times 10^3 joules}{9.63\times 10^3 joules}\times 100=31.15\%$

The percentage efficiency of the machine is 31.15 %.