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anastassius [24]
3 years ago
6

Spinning a loop of wire between the poles of a magnet will induce an electric current. What condition would minimize the induced

current?
A. The plane of the loop is perpendicular to the magnetic field.

B. The magnetic flux through the wire is minimized.

C. The plane of the loop is parallel to the magnetic field.

D. The plane of the loop is halfway between the parallel and perpendicular.
Physics
1 answer:
DochEvi [55]3 years ago
8 0
B. The other choices all happen at some point in the rotation but you want to maximize the flux and then rotate it as fast as possible
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2 years ago
Given a force of 100 N and an acceleration of 10 m/s^2, what is the mass?
frutty [35]

Given:

Force(F): 100 N

Acceleration: 10 m/s^2

Now we know that

F= mx a

Where F is the force acting on the object which is measured in Newton

m is the mass of the object measured in Kg

a is the acceleration measured in m/s^2

Substituting the given values in the above formula we get

100= 10m

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Kobotan [32]

Answer:

False

Explanation:

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3 years ago
Which material reflects the most light transparent, translucent, or opaque?
Svetradugi [14.3K]
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6 0
3 years ago
1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly hori
Dovator [93]

Answer:

The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

<em>A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?</em>

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force (F), measured in newtons:

\Sigma F = F - R -f = F_{net} (1)

Where:

R - Resistance force, measured in newtons.

f - Wind force, measured in newtons.

F_{net} - SUV net force, measured in newtons.

If we know that F = 2500\,N, R = 500\,N and f = 500\,N, then net force experimented by the SUV is:

F_{net} = 2500\,N-500\,N-500\,N

F_{net} = 1500\,N

The car has acceleration.

By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

a_{net} = \frac{F_{net}}{m} (2)

Where m is the mass of the SUV, measured in kilograms.

If we know that F_{net} = 1500\,N and m = 3500\,kg, then the net acceleration of the car is:

a_{net} = \frac{1500\,N}{3500\,kg}

a_{net} = 0.429\,\frac{m}{s^{2}}

The net acceleration of the SUV is 0.429 meters per square second due west.

8 0
2 years ago
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