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Ipatiy [6.2K]
3 years ago
11

You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the oars) toward you, it moves a dis

tance of 1.3 m in a time of 0.96 s. The readout on the display indicates that the average power you are producing is 77 W. What is the magnitude of the force that you exert on the handle?
Physics
1 answer:
tangare [24]3 years ago
5 0

Answer:

56.86153 N

Explanation:

t =Time taken

F = Force

Power

P=\frac{W}{t}\\\Rightarrow W=P\times t\\\Rightarrow W=77\times 0.96\\\Rightarrow W=73.92\ Joules

Work done

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{73.92}{1.3}\\\Rightarrow F=56.86153\ N

The magnitude of the force that is exerted on the handle is 56.86153 N

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An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, (a) the tem
Ivan

Answer:

(b) both the temperature and pressure of the gas decrease.

Explanation:

An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.

6 0
3 years ago
A dc motor with its rotor and field coils connected in series has an internal resistance of 3.2 Ω. When running at full load on
pochemuha

Answer:

The current drawn by the motor from the line is 4.68 A.

Explanation:

Given that,

Internal resistance of the dc motor, r = 3.2 ohms

Voltage, V = 120 V

Emf in the motor, \epsilon=105\ V

We need to find the current drawn by the motor from the line. A dc motor with its rotor and field coils connected in series, applying loop rule we get :

V=\epsilon+Ir

I is current drawn by the motor

I=\dfrac{V-\epsilon}{r}\\\\I=\dfrac{120-105}{3.2}\\\\I=4.68\ A

So, the current drawn by the motor from the line is 4.68 A. Hence, this is the required solution.

7 0
3 years ago
We can expect the force of friction to be greater for an object moving on a surface if the surfaces in contact are
nikitadnepr [17]

Answer:

c

Explanation:

Friction is caused by how rough and object is, and how much the object weighs, as this causes it to drag more.

8 0
2 years ago
A resistor, capacitor, and switch are all connected in series to an ideal battery of constant terminal voltage. Initially, the s
erma4kov [3.2K]

Answer:

The voltage across the resistor is zero, and the voltage across the capacitor is equal to the terminal voltage of the battery.

Explanation:

This is because when a capacitor is charged no current or voltage flows through it so it will have a voltage equal to the terminal voltage of the battery

6 0
3 years ago
An object whose specific gravity is 0.850 is placed in water. What fraction of the object is below the surface of the water?
Fynjy0 [20]

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3

Fraction of the object's weight below the surface of water is calculated as;

= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀

8 0
3 years ago
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